Is there any error in this program

Question

1.00/5 (2 votes)

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#include <stdio.h>
void main()
{
int i,j,rows;
scanf("%d",&rows);
for(i=1;i<=rows;i++)
{
for(j=1;j<=rows;j++)
{
printf("%d",j);
}
printf("\n");
}
}

What I have tried:

I am getting expected ouput:1,23,456,78910
when input:4,your program output:1,12,123,1234

Posted 15-Dec-20 2:56am

Group 15005118

Updated 15-Dec-20 3:45am

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Richard Deeming 15-Dec-20 9:41am

REPOST
You have already posted this homework assignment and accepted a solution:
Is there any error in this program[^]

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k5054 · Answer 1 · 2020-12-15T03:43:00

Quote:
I am getting expected ouput:1,23,456,78910

No you're not. When running this program I get 4 rows of 1234 when input 4.

Quote:
when input:4,your program output:1,12,123,1234

I'm guessing that this is what your assignment is supposed to achieve. Since that's not what's going on I suggest you look into how to use the debugger on your system and find out why that's not happening.

Other notes:
There's no prompt for input, so its not clear when the program is ready for input
main() always returns an int, even if you don't say return 0; at the end, the compiler will add it for you, and you should always declare main accordingly.

Patrice T · Answer 2 · 2020-12-15T03:45:00

Quote:
Is there any error in this program

Short answer: Yes.

Quote:
I am getting expected ouput:1,23,456,78910

Try to make correct sentences. Is it what you want or what you actually get?

Quote:
when input:4,your program output:1,12,123,1234

Your program do not give this output, neither previous one, a simple run should have show it to you.
Your code output is rather

which is none of the outputs

Is there any error in this program

2 solutions

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Solution 2

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