How can I make the following function ? I tried very much but different different errors are occuring

Question

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Write a function with the name “get_companies_names”. The function will be
given a list of dictionaries following the above specifications. The function should
return a list containing “CN” from each dictionary in the given list.
For example, if the above list is given as input to the function, it should simply
return [RS, RS1 , RS2].

What I have tried:

Python

def get_companies_names(companyList):
    final = {}
for i in get_companies_names:
    for k in i :
        if not k in final :
            final[k] = []
        final[k].append(i[k])
        
print(get_companies_names(companyList[
{
        "CN" : "RS" ,
        "CM" : "MOTTO" ,
        "CT" : "KBL" ,
        "CNTRY" : "AFG" ,
        "CNTCT" : {
            "PH" : "0303" ,
            "EM" : "@GM"  ,
            "WS" : ".COM" 
        } ,
        "SA" : {
            "FB" : "FACEBK" ,
            "TW" : "TWITER" ,
            "LI" : "LINKED" 
        }
    },
{
        "CN" : "RS1" ,
        "CM" : "MOTTO1" ,
        "CT" : "KBL1" ,
        "CNTRY" : "AFG1" ,
        "CNTCT" : {
            "PH" : "0304" ,
            "EM" : "@GM1"  ,
            "WS" : ".COM1" 
        } ,
        "SA" : {
            "FB" : "FACEBK1" ,
            "TW" : "TWITER1" ,
            "LI" : "LINKED1" 
        }
    },
{
        "CN" : "RS2" ,
        "CM" : "MOTTO2" ,
        "CT" : "KBL2" ,
        "CNTRY" : "AFG2" ,
        "CNTCT" : {
            "PH" : "0305" ,
            "EM" : "@GM2"  ,
            "WS" : ".COM2" 
        } ,
        "SA" : {
            "FB" : "FACEBK2" ,
            "TW" : "TWITER2" ,
            "LI" : "LINKED2" 
        }
    }
]))

Posted 26-Nov-20 7:33am

Ali Ch0udhary

Updated 26-Nov-20 8:01am

OriginalGriff

v2

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OriginalGriff · Accepted Answer · 2020-11-26T08:01:00

Two things:
1) Indentation in Python is significant:

Python

def get_companies_names(companyList):
    final = {}
for i in get_companies_names:
    for k in i :
        if not k in final :
            final[k] = []
        final[k].append(i[k])

So your function ends immediately after this line:

Python

final = {}

2) Look closely at these two lines:

Python

def get_companies_names(companyList):
...
for i in get_companies_names:

Even if indented properly, are you sure that you want the name of the function in the loop there, instead of the function's parameter?