How to compare value in 2 condition.

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i have 2 integer a and b, which want to used in 2 condition.

C++

int condition1()
{
  if (a==0){
   b=5;
  }
  else(a==1)
   b=7;
  }
  ......
}

C++

int condition2()
{
  if (b==5){
   a=0;
  }
  else(b==7)
   a=1;
  }
  ......
}

What I have tried:

i want as

C++

int condition1()
{
int x;
 check(x);
}

int condition2()
{
int x;
 check(x);
}

int check(int a)
{
 int b
// and i dont know how to write condition in here which use in both condition.
return b;
}

Posted 22-Oct-20 18:53pm

Gautam Naresh

Updated 22-Oct-20 20:11pm

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CPallini · Answer 1 · 2020-10-22T20:11:00

Note that

Quote:
int condition1()
{
if (a==0){
b=5;
}
else(a==1)
b=7;
}
......
}

is not valid code. You should write something like

C++

int condition1()
{
  if (a == 0)
  {
    b = 5;
  }
  else if ( a == 1)
  {
    b = 7;
  }
  //...
}

In order to combine two (or more) conditions, there are the logical operators, gently provided by the programming language, see, for instance: C++ Logical Operators[^].
For example

C++

if ( a == 0 && b ==5)
{
  //do something wonderful here..
}

OriginalGriff · Answer 2 · 2020-10-22T20:10:00

It's not at all clear what you are trying to do, but what is clear is that you are doing it completely wrong.
Your check method returns a value - which is correct - but the code that calls it doesn't use it.
Your condition methods should return a value, but don't.
Your check method takes a parameter, but doesn't use it.
You condition methods don't take a parameter and should.

What I'd suggest is that you think about exactly what you are trying to do, and start working out what values should be parameters and what should be returned.

If what you means is "can I write a function that both condition1 and condition2 can call?" then you will need to be a lot more specific about what it should do - particularly when the value doesn't match either of the if conditions!

How to compare value in 2 condition.

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