How do I can create conastant parameter in C++'s function?

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C++

Python

algorithm

Parameter

I'm trying to rewrite the Python algorithm in C++ and it doesn't work correctly.
I think the problem is that I can't rewrite the function correctly in C++. How do I write a constant to a function (in Python, this is the 'start' parameter) or an error in another one?
On Python 3:

def Algorithm(n, start = 2)

In this instance 'start' - constant.

I dunno how do I can write this on C++

What I have tried:

There is my C++ code:

#include <iostream>
using namespace std;

int Algorithm(int, const int);
int main()
{
	const int start = 2;
	int num, ans;
	cin >> num;
	ans = Algorithm(num, start);
	cout << ans;
	return 0;
}

int Algorithm(int n, const int start = 2)
{
	if (n == 1) {
		return 1;
	}
	else {
		int ans = 0;
		int i;
		for (i = start; i <= n; i++)
		{
			if (n % 1 == 0) {
				ans += Algorithm(n / i, i + 1);
			}
		}
		return ans;
	}
}

And there is my Python code:

def algorithm(n, start=2):
    if n == 1:
        return 1
    else:
        ans = 0
        for i in range(start, n+1):
            if n % i == 0:
                ans += algorithm(n // i, i + 1)
        return ans

n = int(input())
ans = algorithm(n)
print(ans)