How to get the string after the last occurence of split character in Python

Question

0.00/5 (No votes)

See more:

Hi have the following data in the list

(carrier[5].pol[1].tuna)']
(carrier[6].pol[0].tuna)']
(carrier[6].pol[1].tuna)']
(carrier[7].pol[0].tuna)']
(carrier[7].pol[1].tuna)']
(fifo_i)']
(fisu_power_monitor_inst)']
(genblk1[0].MFA_MULT[0].com)']
(genblk1[0].MFA_MULT[1].com)']
(genblk1[0].MFA_MULT[2].com)']
(genblk1[0].MFA_MULT[3].com)']
(genblk1[0].MUX[0].miso)']
(genblk1[0].MUX[0].tuna)']
(genblk1[0].MUX[1].miso)']
(genblk1[0].MUX[1].tuna)']
(genblk1[0].MUX[2].miso)']
(genblk1[0].MUX[2].tuna)']
(genblk1[0].MUX[3].miso)']
(genblk1[0].MUX[3].tuna)']
u_cpri_port']
ul_pac_inst']
pack[0].abc_xyz']
pack[1].abc_xyz']
valid.cstr']

What I have tried:

I want to check each item of the list for a "." and keep the data that comes after "."
I tried the following but it gives me the data before the "." as well

[y  for x in slist for y in x.rsplit('.')]

I also tried the following but it gives me wrong data

[x.strip(".")[-1] for x in slist]

I want my final list to have the following:

tuna)']
tuna)']
tuna)']
tuna)']
tuna)']
(fifo_i)']
(fisu_power_monitor_inst)']
com)']
com)']
com)']
com)']
miso)']
tuna)']
miso)']
tuna)']
miso)']
tuna)']
miso)']
tuna)']
u_cpri_port']
ul_pac_inst']
abc_xyz']
abc_xyz']
cstr']

Posted 6-Oct-20 0:36am

Member 11362771

Updated 6-Oct-20 1:08am

v2

Add a Solution

2 solutions

Solution 2

Python

[y for x in slist for y in x.rsplit('.')[2]]

But that will only work for strings that contain two period characters. You need to pre-process each string to test its format before adding to the new list.

Python

for item in slist:
    set = item.split('.') # try the split
    if len(set) == 3:     # is it a three word set?
        item = set[2]     # only need the last member of the set
    print(item)

Posted 6-Oct-20 1:09am

Richard MacCutchan

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Accepted Answer · 2020-10-06T01:00:00

Solution 1

Try

Python

[ x.split('.')[-1] for x in slist]

Posted 6-Oct-20 1:00am

CPallini

v2

Comments

Richard MacCutchan 6-Oct-20 8:45am

+5, I forgot about -1.

CPallini 6-Oct-20 9:25am

I just discovered it. :-)
Have my 5 as well.

Richard MacCutchan 6-Oct-20 9:56am

Thanks, but your answer is so much more pythonesque.

Member 11362771 6-Oct-20 22:43pm

@CPallini..it worked perfectly

CPallini 7-Oct-20 2:10am

I'm glad of it.