Create a function called xstrlen() which displays the length of a string .

Question

1.00/5 (2 votes)

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C

#include<stdio.h>
#include<string.h>

int xstrlen(char * a);
int main() { 
  char s1[]="bamboo copter";
  char s2[]="doraemon";
  int l1,l2;

 l1= xstrlen(s1);
 l2= xstrlen(s2);
 printf("length of %s is %d\n",s1,l1);
 printf("length of %s is %d\n",s2,l2);
  return 0 ;
}
int xstrlen(char * a){
int length ;
for (a =0;a!='\0';a++){
  length ++;
  
}
}

What I have tried:

C

#include<stdio.h>
#include<string.h>

int xstrlen(char * a);
int main() { 
  char s1[]="bamboocopter";
  char s2[]="doraemon";
  int l1,l2;

 l1= xstrlen(s1);
 l2= xstrlen(s2);
 printf("length of %s is %d\n",s1,l1);
 printf("length of %s is %d\n",s2,l2);
  return 0 ;
}
int xstrlen(char * a){
int length ;
for (a =0;a!='\0';a++){
  length ++;
  //printf("length %d\n",length);
}
}

Posted 5-Oct-20 17:02pm

Random201

Updated 5-Oct-20 20:11pm

CPallini

v3

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Dave Kreskowiak 5-Oct-20 23:34pm

And you had a question or a problem ... ?

2 solutions

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CPallini · Answer 1 · 2020-10-05T20:10:00

You should always compile with all warnings enabled (e.g. -Wall with GCC).
Try

C

#include<stdio.h>

int xstrlen(const char * a);
int main()
{
  char s1[]="bamboo copter";
  char s2[]="doraemon";
  int l1,l2;

  l1  = xstrlen(s1);
  l2  = xstrlen(s2);

  printf("length of %s is %d\n",s1,l1);
  printf("length of %s is %d\n",s2,l2);

  return 0;
}

int xstrlen(const char * a)
{
  int length =0;

  for (length = 0; *a != '\0'; ++a)
  {
    ++length;
  }

  return length;
}

Rick York · Answer 2 · 2020-10-05T17:31:00

Solution 1

Do you have a question?

In case you are asking why your function does not work, it has two issues. It does not initialize the length and it does not return the length.

Posted 5-Oct-20 17:31pm

Rick York