How to get mouse point over picturebox while dragging

Question

5.00/5 (1 vote)

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.NET4.6

Hi All

Developing an windows form application vb, Busy dragging an image bitmap from another control, want to drop this image at the mouse position on the picturebox. The error which i have is that when i drag over the picturebox with the mouse down left button none of the

Handles PBx.MouseMove

are functional.
I have set focus to the Picturebox control ,

Handles PBx.DragEnter

are functional, any ideas on how to bypass the picturebox "locked state" as the left mouse button down when entering the control.
i may have the incorrect mythology in doing this so any assistance appreciated.

Regards
Richard

What I have tried:

Have Searched Google and review some other example apps but others just insert the image into the control as a new image from the Dragged bitmap.

Posted 18-Aug-20 6:56am

Grid-Code

Updated 20-Aug-20 5:43am

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Comments

[no name] 18-Aug-20 16:53pm

Try "MouseEnter" ... can't tell whether your "drag and drop" context is valid. You seem to expect certain behavior.

Grid-Code 19-Aug-20 4:58am

Hi Gerry Schmitz

Private Sub PBx_DragOver(sender As Object, e As DragEventArgs) Handles PBx.DragOver
PBx_ImgIns = New Point(CInt((CSng(Me.PBx.Image.Width) / Me.PBx.Width) * e.X), CInt((CSng(Me.PBx.Image.Height) / Me.PBx.Height) * e.Y))
Console.WriteLine("x : " & PBx_ImgIns.x & " y : " & PBx_ImgIns.y)
End Sub

The above gives e.X & e.Y , but incorrect what i had read up on is that e = Screen Point Location - and not the PBx(PictureBox) Even though PBx.DragOver e not related to PBx Control?
** Trying too get the image pixel point - mouse position
Thanks for the Tip above
Cheers Richard

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Grid-Code · Accepted Answer · 2020-08-20T05:43:00

Private Sub PBx_DragOver(sender As Object, e As DragEventArgs) Handles PBx.DragOver
       'PBx_ImgIns = Image Point
       'PBx = Picturebox Control
       Dim PBxPnt As Point = PBx.PointToClient(New Point(e.X, e.Y)) 'e.Y & e.X = Screen Point
       PBx_ImgIns = New Point(CInt((CSng(Me.PBx.Image.Width) / Me.PBx.Width) * PBxPnt.X), CInt((CSng(Me.PBx.Image.Height) / Me.PBx.Height) * PBxPnt.Y))
   End Sub

If anyone interested code example above gives picturebox control point, then the Picturebox image point, this should work for dropping an object at mouse location on a control