How do I print the address stored in the pointer in C++?

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When I declare a pointer in C, after pointing it to an address I can see the address using the statement:

C++

int *ptr = &var;
printf("%p", ptr);

That will print the address stored in ptr will be printed.
How do I do the same in C++?

I had used a character pointer to point to dynamically allocated memory. I want to the address from which the memory begins.

What I have tried:

I tried to find from internet to do it but couldn't find anything.

Posted 6-May-20 22:09pm

Zeeking99

Updated 6-May-20 23:41pm

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[no name] 7-May-20 4:31am

try void *ptr= &var

KarstenK 7-May-20 9:12am

in your case it is better to use a 'char *p' so everyone (even the compiler) is knowing what you are doing ;-)

2 solutions

Solution 2

My method is a little more basic than Carlo's:

C++

cout << "Pointer value: " << hex << ptr << endl;

However, C++ still supports the printf function.

Posted 6-May-20 23:41pm

Richard MacCutchan

Comments

Zeeking99 7-May-20 9:34am

How does it work? Can you explain it please? I didn't understand how to use it. Thank You.

Richard MacCutchan 7-May-20 10:25am

The hex operator tells the output writer to print the next number in hexadecimal notation. And the next parameter is a pointer which is a memory address, i.e a number.

CPallini 7-May-20 15:58pm

OOOOPS...
My 5.

Zeeking99 8-May-20 0:26am

I understand it now except that it isn't working on my machine. My text editor isn't highlighting the word hex. Usually that means it's not a keyword of the language. Does this hex operator come with a specific version of C++?
Thank You for the answer.

Richard MacCutchan 8-May-20 3:12am

The hex operator is a standard member of the ios class. See <ios> functions | Microsoft Docs[^].

Zeeking99 8-May-20 4:30am

Thank You. I get it now.

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CPallini · Accepted Answer · 2020-05-06T22:38:00

Solution 1

Try

cout << reinterpret_cast<void *>(p) << endl;

Posted 6-May-20 22:38pm

CPallini

Comments

Zeeking99 7-May-20 9:36am

Thank You, It works.