Make this regex ignore spaces

Question

0.00/5 (No votes)

See more:

I have a regex that matches decimal numbers but ignores hex numbers, however if a number has a space it wont work...

Patern

^(\d*\.)?\d+$

20 <- this matches :-)

0x20 <- this is ignored :-)


 20  <-this doesnt match as it has a space :-(

(20 <- this doesnt match either :-(

Can you help guys ? :-)

What I have tried:

Ive tried

^\s(\d*\.)?\d+$

and putting the \s in many different places but no-joy.

Posted 10-Apr-20 3:12am

Bonxy

Updated 10-Apr-20 4:07am

OriginalGriff

v2

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2020-04-10T04:08:00

Your "revised version":

^\s(\d*\.)?\d+$

says that a single space is required at the front, so it will only match if a single space is present.
You can get rounf that with "*" which says "zero of more of these":

^\s*(\d*\.)?\d+$

And you can modify it to allow brackets if you must:

^[\s\(]*(\d*\.)?\d+[\s\)]*$

But ... I'd use string.Trim to remove spaces from both ends, and then use Double.TryParse to convert the value to a number. If it works, great use the numeric version. If it fails, complain to the user! If he's silly enough to expect "(" to be part of a number, then that's his problem...

What I'd actually do is use a NumericUpDown for the input so he can't enter it wrong, but that's up to you ...