How to pass URL retrieved by JS to an action result

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I will try to make this clear. I have an action result that has a View the view use JS to get a URL of a page. I am struggling to pass that url to another Action result that contains the logic. I can't use other approach in my case. Here is the code:

<body>
       
            <div id="data">
                    data goes here:
                @ViewBag.Paramater
            </div>
  
                <script>
                    $(document).ready(function () {

                        var urlPath = top.document.location.href
                        axios.post('/something/CustomPages/62502599-ac48-42b9-b4bf-b211d0341317/Home/Data', {
                            urlValue: urlPath
                        })
                            .then(function (response) {

                                document.getElementById("data").innerHTML = response.data;

                            })
                            .catch(function (error) {
                                console.log(error);
                            });

                    });

                </script>
    </body>

this gets the data and pass it to the other view but i don't know how to pass it to the action result.

What I have tried:

Here is what I tried:
<pre>[HttpPost]
        public ActionResult Index()
        {
            return View();//this use js to get the url
        }
        [HttpPost]
        public ActionResult Data(string urlValue)
        {
           
         //How to pass the url to this Action
              Uri mainURL = new Uri(Request.Form["urlValue"]); //here is the issue
             var artifacrID = HttpUtility.ParseQueryString(mainURL.Query).Get("ArtifactID");
            int DocumentArtifact = Convert.ToInt32(artifacrID);

Posted 9-Mar-20 3:31am

AskalotLearnalot

Updated 9-Mar-20 6:04am

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AskalotLearnalot · Accepted Answer · 2020-03-09T06:04:00

Solution 1

Here is the Solution:
Change this:

Uri mainURL = new Uri(Request.Form["urlValue"]); //here is the issue

To:

Uri mainURL = new Uri(urlValue);

Posted 9-Mar-20 6:04am

AskalotLearnalot