Openfiledialog problem with re-click

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VS2015

Hi,
Iam using VS2015 - Windows Forms. When I click my Browse Button the OpenFileDialog Works good. But Suppose once I Re-click the button after to refresh the form data's, the OpenFileDialog simply hang-up.

I can't understand my problem.. Any of the superiors can guide me?

My Codes

MyFileNameStr = String.Empty;
openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "D:\\";
openFileDialog1.Filter = "(*.xlsx)|*.xls| All files (*.*)|*.*";
openFileDialog1.RestoreDirectory = true;
openFileDialog1.Title = "Select Your Attachment File :- ";
openFileDialog1.FileName = "";
if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK && openFileDialog1.FileName.Length>0) {
    String MyDrawingFile = Path.GetFileName(openFileDialog1.FileName);
    myDataGrid1.CurrentRow.Cells["MyExcel_file"].Value = Path.GetFileName(openFileDialog1.FileName);
    MyFileNameStr = openFileDialog1.SafeFileName.ToString();
    MyFileNameStrs = openFileDialog1.SafeFileName.ToString().Split('_');
}

Thank Again

What I have tried:

Tried to Read the FileName using OPenFileDailog Control.

Posted 27-Dec-19 23:30pm

Paramu1973

Updated 6-Jan-20 21:18pm

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3 solutions

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OriginalGriff · Answer 1 · 2019-12-28T00:18:00

We can't tell - we can't run your code under exactly the same circumstances you can, and you need that to work out what is going wrong.

So, it's going to be up to you.
Fortunately, you have a tool available to you which will help you find out what is going on: the debugger. If you don't know how to use it then a quick Google for "Visual Studio debugger" should give you the info you need.

Put a breakpoint on the first line in the function, and run your code through the debugger. Then look at your code, and at your data and work out what should happen manually. Then single step each line checking that what you expected to happen is exactly what did. When it isn't, that's when you have a problem, and you can back-track (or run it again and look more closely) to find out why.

Sorry, but we can't do that for you - time for you to learn a new (and very, very useful) skill: debugging!

Dave Kreskowiak · Answer 2 · 2019-12-28T04:33:00

Where did you define "openFileDialog1" and where is the code that disposes the instance you created?

Your code seems to be structured wrong. You should have a method that creates and shows the dialog, determines if there is a file picked, disposes the dialog, then returns the filename that was picked.

Paramu1973 · Answer 3 · 2020-01-06T21:18:00

The below code solves the problem...

openFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "D:\\";
openFileDialog1.Title = "Select Your Attachment File :- ";

openFileDialog1.CheckFileExists = true;
openFileDialog1.CheckPathExists = true;
openFileDialog1.Filter = "exe files | *.exe|All files (*.*)|*.*";

openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
openFileDialog1.ReadOnlyChecked = true;
openFileDialog1.ShowReadOnly = true;

if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK) {
MyDrawingFile = System.IO.Path.GetFileName(openFileDialog1.FileName).ToString();
MyFileNameStr = System.IO.Path.GetFileNameWithoutExtension(openFileDialog1.FileName).ToString();
}

Thanks

Openfiledialog problem with re-click

3 solutions

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