Sum of a function over a serious of numbers Python

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say I have a function f(x) were x is n^2. and say I wanted to sum the result of n^ for range of 1 - 10.

Does python have anything similar to mathmatica that would allow me pass a math function and sum the results or am I limited to a for loop

What I have tried:

so something like

Python

for n in range(1, 10):
    result += (n**2)

Posted 7-Nov-19 7:46am

Nightpoison

Updated 7-Nov-19 8:25am

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2 solutions

Solution 1

Try this, where the sum() function accepts a list.

Python

result = sum([x**2 for x in range(1,11)])

Posted 7-Nov-19 8:18am

Richard MacCutchan

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CPallini 7-Nov-19 14:26pm

5.You've been faster.

Nightpoison 12-Nov-19 7:52am

Hi, Thanks for the quick post. I appreciate Question,isn't this more or less the same thing as my for loop. I"m not 100% on python and what occurs in the background. but with the exception of calling the sum function, this still contains a for loop. Is it anymore efficient?

Richard MacCutchan 12-Nov-19 11:19am

Whether it is explicit or implicit, you cannot sum a set of numbers without a repeated for loop.

Nightpoison 19-Nov-19 8:40am

Richard, thank you for that clarification. That makes sense to me.

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CPallini · Accepted Answer · 2019-11-07T08:26:00

Solution 2

Yes.

Python

result = functools.reduce(lambda a,b: a + b*b, range(1,11))

See, for instance: Functional Programming HOWTO — Python 3.8.0 documentation[^].

Posted 7-Nov-19 8:26am

CPallini

Comments

Richard MacCutchan 7-Nov-19 14:29pm

I cheated and used Google. :)

CPallini 7-Nov-19 16:56pm

Great minds think alike :-) I am not a Python coder,

Nightpoison 12-Nov-19 8:12am

from my understand lamdas are that efficient of a tool. While I never mentioned efficiency as a prereq, I should have. But you did answer my question.

I personally haven't spent much time looking at lambda functions.