Bootable Prog.

Question

0.00/5 (No votes)

See more:

Can I Write My Addition program
such that it will boot the system, or will execute such that it will not require OS support.

In short Bootable Addition Program.

Posted 12-Jan-10 22:04pm

PGKulkarni

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Answer 1 · 2010-01-12T22:18:00

Solution 2

A guy, here at CodeProject is doing it.
He has written an article series about [^].
Do you realize it is a daunting task?
:)

Posted 12-Jan-10 22:18pm

CPallini

Christian Graus · Answer 2 · 2010-01-12T22:08:00

What do you mean by 'addition program' ? Any program that 'will not require OS support' will, by definition, be an operating system of sorts, presenting at a minimum, display drivers and drivers for taking input from the user. The answer is almost certainly, therefore, no, to that half. How do you mean, you want a program to 'boot the system' ? Some motherboards offer wake on LAN, but a program that's on a computers HDD, cannot execute or do anything, if that computer is off.