Printer error function

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It is a question that I encountered in a competitive programming site. The question asked to return the value count/n

I have attached my codes and I only want to know how to write the return statement. And note that the output should be of the format count/n and not in decimals.

What I have tried:

def printer_error(s):
count = 0
n = len(s)
for i in s:
if i in ["n","o","p","q","r","s","t","u","v","w","x","y","z"]:
count += 1

Posted 9-Aug-19 20:02pm

Member 14517556

Updated 9-Aug-19 22:39pm

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2 solutions

Solution 1

Um ...

Python

return count/n

Posted 9-Aug-19 20:09pm

OriginalGriff

Comments

Member 14517556 10-Aug-19 2:51am

I think you didn't understood my point. I want return value in fractions and not in decimals. Your code will give return value in decimals.

OriginalGriff 10-Aug-19 3:08am

The only way to "return a fraction" is to either return two values (which you can) or to return a string made up of the two values.
Python doesn't have a "fractions type"!

I'd suggest going back to your site and reading the instructions really carefully!

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Patrice T · Accepted Answer · 2019-08-09T22:40:00

Solution 2

did you try this?

Python

return str(count)+"/"+str(n)

Posted 9-Aug-19 22:40pm

Patrice T

Comments

Member 14517556 10-Aug-19 23:58pm

Never actually come to my mind. Thank you

Patrice T 11-Aug-19 0:42am

You're welcome.
If your question is solved, you can accept the answer, it will close the question.

Member 14517556 11-Aug-19 1:11am

Oh sorry forgot to do so.Thank you again

Patrice T 11-Aug-19 1:30am

No problem