How do I get java and .NET version information in shell script

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Hi,
I am new in shell script. I create one script file and try to run in Windows 10. For this I installed ubuntu. When I run the bash file without function scope, its working. As example

var=$(java -version 2>&1 | awk -F '"' 'NR==1 {print $2}')
echo $var

But if I call them inside a function its not working.

What I have tried:

Bash

#!/bin/bash
myfunc()
{
  echo "$(java -version 2>&1)" | grep "java version" | awk '{ print substr($3, 2, length($3)-2); }'
}



myfunc

Posted 31-Jul-19 0:38am

bigyan sahoo

Updated 31-Jul-19 4:15am

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Comments

Richard MacCutchan 31-Jul-19 9:42am

I note that the code in myfunc is different from the code that works. Try running it step by step outside of the function to see which part is failing.

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k5054 · Answer 1 · 2019-07-31T04:16:00

The default java installation for ubuntu is openjdk, not the version from Oracle. This means that java -version shows

$ java -version
openjdk version "11.0.3" 2019-04-16
OpenJDK Runtime Environment (build 11.0.3+7-Ubuntu-1ubuntu218.04.1)
OpenJDK 64-Bit Server VM (build 11.0.3+7-Ubuntu-1ubuntu218.04.1, mixed mode, sharing)

grep "java version" isn't going to find a match, thus the function returns nothing.

Points to Richard for pointing out that your code is different between mycode and the var = versions.