How to view raw content of a POST request.

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I'm trying to 'fake' an HTTP POST request to my online SMS service, so I don't have to load their page everytime I want to send SMS's. It's quite a simple page, with a file uploaded input and some sundry fields. I suspect a server side PHP page is rendering the web page I see, as well has handling 'postbacks'. To find out how to structure the FormData of the POST request, I would like to view such a request in Firebug, but the current view shows the POST data as:

Content-Type: multipart/form-data; boundary=---------------------------231991966824484
Content-Length: 1493

-----------------------------231991966824484
Content-Disposition: form-data; name="rm"

memberssmsbatch
-----------------------------231991966824484
Content-Disposition: form-data; name="Action"

Send

I'm sure this isn't what the actual body of the request looks like. How can I view that:

Posted 10-Jan-10 4:20am

Brady Kelly

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Abhinav S · Answer 1 · 2010-01-10T05:32:00

Solution 1

Try using Fiddler[^].

Posted 10-Jan-10 5:32am

Abhinav S

Updated 10-Jan-10 5:45am

v4