How to separate the string and save into two variables

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How to separate the string and save into two variables.but this value of string is coming from the table of combination of two fields.now i want to separate it into two fields

C#

string jobHeading = Session["selectedJobHeading"].ToString();

   //in jobHeading string the value will come like this(jobposition in companyname) here jobposition and comapanyname are fields

                    string jobposting = (jobHeading.Split('in'))[0];

                    string companyname = (jobHeading.Split('in'))[1];

Posted 13-Dec-12 21:18pm

ntitish

Updated 13-Dec-12 21:25pm

Krunal Rohit

v2

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[no name] 14-Dec-12 3:20am

any efforts so far ?? Code ??

ntitish 14-Dec-12 3:24am

string jobHeading = Session["selectedJobHeading"].ToString();

//in jobHeading string the value will come like this(jobposition in companyname) here jobposition and comapanyname are fields

string jobposting = (jobHeading.Split('in'))[0];

string companyname = (jobHeading.Split('in'))[1];

ntitish 14-Dec-12 3:26am

and i want to separate that two fields and want to save in two variables.
can u answer me fast sir.

ntitish 14-Dec-12 3:28am

sir it is saying that have so many charterers in a literal

ntitish 14-Dec-12 3:51am

string[] parts = jobHeading.Split(" in ");
if (parts.Length == 2)
{
string jobposting = parts[0];
string companyname = parts[1];
...
}

THIS WAS THE ERROR I AM GETTING AFTER APPLYING

Error 91 The best overloaded method match for 'string.Split(params char[])' has some invalid arguments D:\nageswararao\dec-14-12-morning\Alumini_App\Alumini_App\jobpostdisplay.aspx.cs 104 38 Alumini_App

ntitish 14-Dec-12 8:24am

thanks bro for spending valuable time for me............

ntitish 14-Dec-12 8:24am

at last i got the answer

2 solutions

Solution 3

You may solve the problem only if one (or both) of the following conditions hold:

The composing substrings are of fixed length.
There is a separator (that is special character) between the composing substrings.
There is another unique method for distinguishing the substrings (e.g. they belong to two different sets).

If condition 1 holds then use the String.Substring[^] method.

If condition 2 holds then use the String.Split[^] method.

If condition 3 holds then you should exploit the 'distinguishing method'.

Posted 13-Dec-12 21:29pm

CPallini

Comments

ntitish 14-Dec-12 4:00am

string[] parts = jobHeading.Split(" in ").ToString();
if (parts.Length == 2)
{
string jobposition = parts[0];
string companyname = parts[1];
}
after applying this i am getting this error
Error 91 The best overloaded method match for 'string.Split(params char[])' has some invalid arguments D:\nageswararao\dec-14-12-morning\Alumini_App\Alumini_App\jobpostdisplay.aspx.cs 104 38 Alumini_App

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OriginalGriff · Accepted Answer · 2012-12-13T21:30:00

Solution 4

Change the quotes to double quotes:

C#

string jobposting = (jobHeading.Split('in'))[0];

string companyname = (jobHeading.Split('in'))[1];

Becomes

C#

string jobposting = (jobHeading.Split("in"))[0];

string companyname = (jobHeading.Split("in"))[1];

But it would be better to do the split once, and check it, and to include the spaces in the split:

C#

string[] parts = jobHeading.Split(" in ");
if (parts.Length == 2)
   {
   string jobposting = parts[0]; 
   string companyname = parts[1];
   ...
   }

Posted 13-Dec-12 21:30pm

OriginalGriff

Comments

ntitish 14-Dec-12 3:53am

string[] parts = jobHeading.Split(" in ");
if (parts.Length == 2)
{
string jobposting = parts[0];
string companyname = parts[1]; ...
}
THIS WAS THE ERROR I AM GETTING AFTER APPLYING

Error 91 The best overloaded method match for 'string.Split(params char[])' has some invalid arguments D:\nageswararao\dec-14-12-morning\Alumini_App\Alumini_App\jobpostdisplay.aspx.cs 104 38 Alumini_App

OriginalGriff 14-Dec-12 4:07am

Sorry, brain death has occurred - probably due to a lack of coffee...
string[] parts = jobHeading.Split(new string[] { " in " }, StringSplitOptions.None);

CPallini 14-Dec-12 4:13am

I wonder why they didn't make an overload for the single string/character.

OriginalGriff 14-Dec-12 4:28am

I know what you mean: I kept trying to use one, so I wrote an extension method - hence I got caught when I posted here... :doh:

ntitish 14-Dec-12 4:40am

Error 32 Array creation must have array size or array initializer D:\nageswararao\dec-14-12-morning\Alumini_App\Alumini_App\jobpostdisplay.aspx.cs 104 65 Alumini_App
after applying what u said

OriginalGriff 14-Dec-12 5:00am

I think you typed it wrong - show the code for line 104, I think you mistyped "(" and ")" for "{" and "}"

ntitish 14-Dec-12 5:33am

string[] parts = jobHeading.Split(new string[]( " in " ),StringSplitOptions.None);
if (parts.Length == 2)
{
string jobposition = parts[0];
string companyname = parts[1];
}

OriginalGriff 14-Dec-12 5:36am

Look at the original code, then at yours.
See the curly brackets in mine? See you have replaced them with round brackets?
(they are the ones around " in " if you can't see it - you have
(" in ")
I have
{" in "}

ntitish 14-Dec-12 5:40am

thanks a lot bro...........at last i got it.
how intelligent you people are.....i am the fresher for this job .thanks a lot

OriginalGriff 14-Dec-12 5:48am

You're welcome!