Unary operator overloading

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C++

overloading

Is this correct?
Unary operator overloaded by means of a friend function takes one reference argument.

Thanks!

Posted 4-Oct-12 3:06am

NexusNemesis

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eugene.shikhov · Accepted Answer · 2012-10-04T04:36:00

Solution 1

not exactly. take a look at the tutorial:
Overloading unary operators +, -, and ![^]
Overloading operators using member functions[^]
Overloading the increment and decrement operators[^]

Posted 4-Oct-12 4:36am

eugene.shikhov

Comments

Stefan_Lang 4-Oct-12 11:01am

Well he did specifically ask about friend function overloading, and in that case he would be correct. Your first link does it exactly that way, the other two links use member functions instead.

eugene.shikhov 5-Oct-12 6:47am

NexusNemesis asked about definition of the term "unary operator overload" and cited wrong one.

Stefan_Lang 5-Oct-12 10:47am

Don't omit "by means of a friend function". He is correct in that case.

eugene.shikhov 10-Oct-12 4:30am

Well, "by means of a friend function" is in the definition part of the sentence, not in the term one. And, generally, that definition is wrong, because it describes only one particular case.

Stefan_Lang 10-Oct-12 4:59am

That is not my understanding, but since the question is sufficiently answered, there is no point in arguing about grammar ;-)