Php - how do I check if today's day and month are equal to Y-m-d column in mysql database?

Question

0.00/5 (No votes)

See more:

Greetings everyone!

I'm trying to configure my system to save birthday wishes to my database, but I'm stuck with the PHP code. I need to check if today's month and day match the month and day in the birthday (Y-m-d) field dob of the database. I really appreciate your time and help. Thanks a million!

JC.

What I have tried:

PHP

if (date('Y-m-d') == $dados4['dob']) {
    $sql06 = "INSERT INTO comunicacao (enviar_para, titulo, descricao, tipo, curso, modulo, data_cadastro, hora_cadastro) VALUES ('".$_SESSION['usuarioId']."','Happy Birthday!','We wish you all the best on this very soecial day.','Todos','Todos','Todos','".date('Y-m-d')."','".date('H:i:s')."')";
    $query06 = mysqli_query($mysqli, $sql06);
}

Posted 22-May-19 6:58am

JC Carmo

Updated 23-May-19 0:44am

v2

Add a Solution

Comments

[no name] 22-May-19 21:34pm

You spelled "special" wrong.

Richard MacCutchan 23-May-19 8:16am

Why are you storing that message in the database? The only item you need to save is the date of birth.

Richard Deeming 24-May-19 14:40pm

PHP: SQL Injection - Manual[^]

In this particular instance, you might get away with it, assuming the $_SESSION['usuarioId'] is an integer, or at least something that can't be controlled by the user.

But using string concatenation / interpolation to build SQL queries a bad habit to get into, and will definitely leave your code vulnerable in the future.

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

phil.o · Answer 1 · 2019-05-23T00:44:00

You only have to check that the day and month parts are equal for both values; the year part does not count.

PHP

$today = getdate();
$birthday = date_parse($dados4['dob']);
if (
      $today['mday'] == $birthday['mday']
   && $today['mon']  == $birthday['mon']
)
{
   /* Birthday */
}
else
{
   /* Not birthday */
}