How do you create 2 random values

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I wrote

<br />            Random RollOne = new Random();<br />            Random RollTwo = new Random();<br />                dieOne = RollOne.Next(1, 7);<br />                dieTwo = RollTwo.Next(1 , 7);<br />                sum = dieOne + dieTwo;<br />

but dieOne and dieTwo are always equal, how do you make two independent random values?

Edit:
Thanks Mikanu, it works now.

modified on Monday, July 13, 2009 10:43 PM

Posted 13-Jul-09 15:55pm

Nathan Revka

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PIEBALDconsult · Answer 1 · 2009-07-13T17:30:00

Solution 1

You should create one instance of Random as a static field of the class and use it whenever you need it.
It should never be a local variable of a method.

Posted 13-Jul-09 17:30pm

PIEBALDconsult

mikanu · Answer 2 · 2009-07-13T16:00:00

The correct way to do that is to create an instance of the Random class and then call one of the following methods:
- Next(Int32 max) // will return a random number smaller than max
- NextByte() // will return a random byte (between 0 and 255)
- NextDouble() // will return a random number between 0.0 and 1.0<br />

Here's a code sample which will generate two random numbers, a and b, between 0 and 10

<br />Random rnd = new Random();<br />int a = rnd.Next(10);<br />int b = rng.Next(10);<br />