C# retrieve the style, name, and size value of a fontdialog

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Hello,
My question is in the title ...
I can get the name, the size, but not the Style..What do you miss me?
Thank you

What I have tried:

<pre lang="c#"> 
                   FontDialog Dlg = new FontDialog
                {
                    ShowColor = false,
                    ShowApply = false,
                    ShowEffects = false,
                    ShowHelp = false,
                   //   AllowVerticalFonts = false,
                    //  AllowScriptChange = false,
                   //   FixedPitchOnly = true,
                    MinSize = 9,
                    MaxSize = 16
                };


 if (Dlg.ShowDialog() == DialogResult.OK)
                {                 
                    string fontName = Dlg.Font.Name;
                     fontStyle = Dlg.Font.Style; // This code does not work ....
                    float fontSize = Dlg.Font.Size;

                    TxtPolice.Text = fontName;
                    TxtStyle.Text = fontStyle; // This code does not work ....
                    TxtFont.Text = "" + fontSize;
                }

Posted 14-May-19 6:59am

LSB71

Updated 14-May-19 20:17pm

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Comments

Richard Deeming 14-May-19 13:29pm

What does "does not work" mean? Provide the full details of any errors you're getting.

3 solutions

Solution 3

C#

FontDialog Dlg = new FontDialog
                {
                    ShowColor = false,
                    ShowApply = false,
                    ShowEffects = false,
                    ShowHelp = false,
                   //   AllowVerticalFonts = false,
                    //  AllowScriptChange = false,
                   //   FixedPitchOnly = true,
                    MinSize = 9,
                    MaxSize = 16
                };


                if (Dlg.ShowDialog() == DialogResult.OK)
                {                 
                    string fontName = Dlg.Font.Name;
                    FontStyle fontStyle = Dlg.Font.Style;
                    float fontSize = Dlg.Font.Size;

                    TxtPolice.Text = fontName;
                    TxtStyle.Text = fontStyle.ToString();
                    TxtFont.Text = "" + fontSize;
                }

Posted 14-May-19 20:17pm

LSB71

Comments

BillWoodruff 15-May-19 22:55pm

Every one of those six Fields declared in the scope of the if clause will not exist outside the if clause, and can never be used.

LSB71 19-May-19 2:55am

Hello,
Thank you, how should I declare them then?

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phil.o · Accepted Answer · 2019-05-14T07:42:00

Solution 1

C#

fontStyle = Dlg.Font.Style;

You are using here a fontStyle variable which it seems you did not declare. Try

C#

System.Drawing.FontStyle fontStyle = Dlg.Font.Style;

instead. You can also import System.Drawing namespace so that you can reference the FontStyle enumeration in a shorter way.

Posted 14-May-19 7:42am

phil.o

Comments

BillWoodruff 15-May-19 22:57pm

relevant, but does not address the main issue.

LSB71 · Accepted Answer · 2019-05-14T07:42:00

Hello,
Thank you, but I have solved my story ....
Here is the complete code:

C#

FontDialog Dlg = new FontDialog
         {
             ShowColor = false,
             ShowApply = false,
             ShowEffects = false,
             ShowHelp = false,
            //   AllowVerticalFonts = false,
             //  AllowScriptChange = false,
            //   FixedPitchOnly = true,
             MinSize = 9,
             MaxSize = 16
         };


         if (Dlg.ShowDialog() == DialogResult.OK)
         {
             string fontName = Dlg.Font.Name;
             Object fontStyle = Dlg.Font.Style;
             float fontSize = Dlg.Font.Size;

             TxtPolice.Text = fontName;
             TxtStyle.Text = fontStyle.ToString();
             TxtFont.Text = "" + fontSize;
         }

C# retrieve the style, name, and size value of a fontdialog

3 solutions

Solution 1

Solution 2

Solution 3

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