How to check if list contains a particular value?

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I get new current list randomly but the randomly generated list should have TRUE in it,
eg.['TRUE','FALSE' , 'FALSE', 'FALSE',] or ['FALSE' , 'FALSE', 'FALSE','TRUE']

Python

import random

list2 = ['TRUE','FALSE' , 'FALSE', 'FALSE', 'FALSE','FALSE','FALSE' ]
current = []

def randompicker():
    for i in range(4):
        current.append(random.choice(list2))
      
randompicker()


s = current

What I have tried:

Python

for x in s:
    if 'TRUE' in x:
        print (x)

Posted 8-May-19 16:45pm

Dechen Wangmo

Updated 8-May-19 20:15pm

Patrice T

v2

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Comments

Richard MacCutchan 9-May-19 3:43am

You cannot use the expression if 'TRUE' in x, as x is not a list. It should be just

if 'TRUE' in s:

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Maciej Los · Accepted Answer · 2019-05-08T20:16:00

Quote:

You can use this syntax:

Python
if myItem in list:
    # do something
Also, inverse operator:

Python
if myItem not in list:
    # do something
It's work fine for lists, tuples, sets and dicts (check keys).

Note that this is an O(n) operation in lists and tuples, but an O(1) operation in sets and dicts.

source: python - Is there a short contains function for lists? - Stack Overflow[^]

The same is stated here: Python : How to Check if an item exists in list ? | Search by Value or Condition – thispointer.com[^]