find the index of a 2D array

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How would I get the index of the 2D array? For example, I would like to get the index of the spectrumList array at some point below in the code but this doesn't work
int index = spectrumList[j];

C#

for (int j = 0; j < spectrum.spectrum.GetLongLength(1); j++)
                        {
                             double mass = spectrum.spectrum[0, j];
                             double intensity = spectrum.spectrum[1, j];
                             double[] m = new double[2];
                             m[0] = mass;
                             m[1] = intensity;
                             masses[j] = mass;
                             intensities[j] = intensity;
                             spectrumList[j] = m;


                        }

Posted 10-Feb-12 9:36am

shekarchee

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BillWoodruff 10-Feb-12 18:51pm

Until you give us the details of the structure of 'spectrum, I don't think we can help you.

Seeing a construction like "spectrum.spectrum" is ... very strange.

My intuitive sense is that this code could be highly improved by use of Generics.

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Christian Graus · Answer 1 · 2012-02-10T10:18:00

Solution 1

Is spectrumlist a 1D array of ints ? You say 2D array in your question, in which case, spectrumList[j] returns a 1D array, not an int. When you say 'does not work', that is useless. Tell us what happens, what any error message is, etc. I am left guessing what your error is, but I think it's that you need to index the second array to get to an int.

Posted 10-Feb-12 10:18am

Christian Graus

Comments

BillWoodruff 10-Feb-12 18:47pm

imho this is a comment to try and help clarify the question asked, and should be posted as a comment, not a solution.

Christian Graus 10-Feb-12 20:55pm

He says it's a 2D array and he deals with it as a 1D array. So therefore it's very likely that I've told him what is wrong, and I will come back and tell him more, if he gives me enough info to do so. I'm not sure I deserve a 1 vote for giving a probable answer and making a commitment to keep helping until the answer is found.