Finding all childern of a parentid in sqlserver

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hello friends i have a table like this.

ID Parent
1 Null
2 1
3 2
4 Null
5 1
6 4

Now i want to count all children for a parent id in this table up to n level. like ID 1 have 3 children, 4 has 1 child , 2 has one and so on. Please help me , how can i achieve that .
thanks in advance friends.

Posted 14-Jan-12 17:50pm

pawanvats

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2 solutions

Solution 2

try this...

create function [dbo].[myfunction]
(
@p_P int
)
returns int
begin
declare @output int
select @output=count(*) from P_table where parent=@p_P
return @output
end
go
select distinct parent, dbo.myfunction(parent) as 'No of child(ren)' from p_table

Posted 14-Jan-12 19:24pm

psychic6000

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Amir Mahfoozi · Accepted Answer · 2012-01-14T21:14:00

Firstly, have a look at the output of this query :

SQL

declare @nodeid int
set @nodeid = 109;

with rootCTE(id, parentid, level )
as
(
select id, parent ,1
from table
    where parent = @nodeid

union all
select e.id, e.parent , r.level+1 from table t, rootCTE r where t.parent = r.id
)
select * from rootCTE

Then to get the count of children up to level 2 run this one :

SQL

declare @nodeid int
set @nodeid = 109;

with rootCTE(id, parentid, level )
as
(
select id, parent ,1
from table
    where parent = @nodeid

union all
select e.id, e.parent , r.level+1 from table t, rootCTE r where t.parent = r.id
)
select COUNT(*)  from rootCTE
where level<=2

To count all children remove the where clause.