SQL Query Stored Procedure Wrong Help.

Question

0.00/5 (No votes)

See more:

CREATE PROCEDURE Transfer
@orderValue int,
@custFName nvarchar(20),
@custLName nvarchar(20)
AS
UPDATE [Money]
FROM CustomerBankInfo
INNER JOIN Customer
ON CustomerBankInfo.CustomerID = Customer.CustomerID
SET [Money] = [Money] - @orderValue;
WHERE Customer.FirstName = @custFName AND Customer.LastName = @custLName

"INCORRECT SYNTAX NEAR '='"

SET [Money] = [Money] - @orderValue;

What am I doing wrong? Could someone help me out please.

Posted 12-Dec-11 11:39am

WurmInfinity

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Eduard Lu · Accepted Answer · 2011-12-12T11:45:00

Solution 1

You cannot join two tables in update statement. You can use subqueries instead. Try the ff. codes:

SQL

UPDATE CustomerBankInfo
SET Money = (money - @ordervalue)
WHERE CustomerBankInfo.CustomerID = (SELECT CustomerID
                                     FROM Customer
                                     WHERE Firstname = @custFName
                                     AND LastName = @custName)

Posted 12-Dec-11 11:45am

Eduard Lu

Comments

WurmInfinity 12-Dec-11 17:58pm

You Sir, are a God among men. Thanks a lot :)

[no name] 12-Dec-11 20:07pm

you are welcome :)