Calculate total working hours where hours passed as a number

Question

5.00/5 (2 votes)

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I am using FLEX version 3.0 I want to calculate the total working hours. I am giving you the details and what i have done in it.

var a:Number = 2.00;
var b:Number = 2.00;
var c:Number = 1.45;
var d:Number = 1.30;

var total:Number = a+b+c+d;
var totalmin:int = total;
var temp:Number = total - totalmin;
var tem2:Number = 0.60 - temp;
var workhour:Number = 0;

while(total >= 0)
{
   workhour += 1;
   total -= 1.00;
}

var tot:Number = workhour + tem2;

txtTotal.text = tot.toString();

I want result 7.15 not 6.75. currently i am getting 6.85... please Help to solve this issue.

thanks in advance.

Posted 8-Dec-11 22:09pm

Sagar Rawal

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3 solutions

Solution 1

Could it have anything to do with the fact that an hour contains 60 minutes, not 100? So 1 3/4 hours is not 1.45, but 1.75? and 1 1/2 hours is not 1.30 but 1.50?

Posted 8-Dec-11 22:25pm

OriginalGriff

Comments

Sagar Rawal 9-Dec-11 4:31am

User can enter anything between 0 to 60. but that all in number that's why i am facing problem. he/she can enter 1.23 + 2.42 then total time is 4.05 not 3.65.....

OriginalGriff 9-Dec-11 4:40am

I would convert the user input to mnutes, and do all work on that. Then convert back to hours and minutes at the end. What if you end up with four inputs of 1 hour, 45 minutes? The total is 7 hours, but your code only allows for one 60 minute overflow. Converting to minutes for everything solves this without complicating the code.

TorstenH. 9-Dec-11 4:39am

you're right. Typical problem dealing with time.
I suggest to use Date objects, not Integer values. That solves the problem and gives a stable performance.
It's a bit more coding but worth it.

LanFanNinja 9-Dec-11 4:46am

+5 I agree with this solution and the comments.

Solution 2

On this line

C#

var tem2:Number = 0.60 - temp;

you need to reverse the order of subtraction like so

C#

var tem2:Number = temp - 0.60;

this will give you a total of 7.15

Posted 8-Dec-11 22:28pm

LanFanNinja

Comments

Sagar Rawal 9-Dec-11 4:40am

still not the right answer in following data
var a:Number = 2.33;
var b:Number = 2.00;
var c:Number = 1.45;
var d:Number = 1.45;

LanFanNinja 9-Dec-11 4:46am

Sorry I was only going by the values posted in your question. I agree with the comments posted in solution 1 and I think you should rewrite this code using there suggestions.

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Savalia Manoj M · Accepted Answer · 2011-12-08T23:14:00

I have worked a lot on this one and find one of the interesting questions..... and i have found the correct answer for that.. Keep posting that interesting questions.

here is the code.

var a:Number = 2.23;
var b:Number = 2.36;
var c:Number = 1.18;
var d:Number = 1.13;

var totalHours = 0.0;

var inta:int = a;
var numa:Number = a - inta;
var intb:int = b;
var numb:Number = b - intb;
var intc:int = c;
var numc:Number = c - intc;
var intd:int = d;
var numd:Number = d - intd;


var total:int = inta + intb + intc + intd;
var totalsec:Number = numa + numb + numc + numd;
var tempsec:int = totalsec * 100; 

var temp:int = tempsec/60;

total += temp;

var sec:Number = tempsec - (temp*60);

sec = sec/100;

totalHours = total + sec;

txtTotal.text = totalHours.toString();