check The status of the Field

Question

0.00/5 (No votes)

See more:

, +

I created 1o sub job of the parent job id...
i display the status of all the job when click the link of parent job id in grid view...when i click parent id it display the all the sub job of the parent job id...

i have to perform some action if all sub job submitted flag true ...if any of the job not submitted i cant do my work ...how to check my all sub job submitted...

Posted 13-Nov-11 22:32pm

shwiuwew

Updated 13-Nov-11 23:42pm

v2

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

thatraja · Accepted Answer · 2011-11-13T22:50:00

Solution 1

Use CURSOR[^] or its alternatives(WHILE loop, User Defined Functions, Temp table, Table variables, etc.,)

Check this answer
CURSOR & its alternatives[^]

Posted 13-Nov-11 22:50pm

thatraja