position of picture in C#

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C#

Bitmap ax = new Bitmap(300, 300);
Rectangle rc = new Rectangle(0, 0, 300, 300);
this.DrawToBitmap(ax, rc);
pictureBox1.Image = ax;

after running this code we have an image of part of form (from point(0,0) to point(300,300)) but i want an image from point(300,300) to point(600,600).
How I can do it?

Posted 13-Sep-11 21:23pm

AmirAli1374

Updated 13-Sep-11 21:31pm

OriginalGriff

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OriginalGriff · Answer 1 · 2011-09-13T21:31:00

DrawToBitmap only draws from the TLHC of the source control, as it assumes that the whole control (in this case, probably an entire form) will be required. If you want just a portion, then you need to draw the whole control into a suitable bitmap, then draw a portion of that image into a new bitmap.

C#

Bitmap imageOfControl = new Bitmap(600, 600);
Rectangle rc = new Rectangle(0, 0, 600, 600);
this.DrawToBitmap(imageOfControl , rc);
Bitmap ax = new Bitmap(300,300);
using (Graphics g = Graphics.FromImage(ax))
   {
   g.DrawImage(imageOfControl, new Rectangle (300, 300, 300, 300), new Rectangle(0, 0, 300, 300), GraphicsUnit.Pixel);
   }
imageOfControl.Dispose();
pictureBox1.Image = ax;

BobJanova · Answer 2 · 2011-09-14T00:02:00

Solution 2

pictureBox1 must be a control on the form. Try moving the picture box to an origin of (300, 300).

Posted 14-Sep-11 0:02am

BobJanova