How can i generate random decimal numbers in unique

Question

1.00/5 (1 vote)

See more:

Hi How can i generate random decimal numbers

C#

public static string createRandomNumbers(int Length)
       {
           

           string _allowedChars = "1234560789";
           Random randNum = new Random();
           char[] chars = new char[Length];
           int allowedCharCount = _allowedChars.Length;

           for (int i = 0; i < Length; i++)
           {
               chars[i] = _allowedChars[(int)((_allowedChars.Length) * randNum.NextDouble())];
           }

           return new string(chars);

       }

This code for generating random numbers

like This i want to generate random decimal numbers

how to get random decimal numbers

data type decimal(8,2) that is 8 digit after point 2 digit
like dis i will pass two length..for this how can able to write function? ...

Posted 23-Jun-11 2:09am

suryaswathi

Updated 17-Apr-16 9:15am

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Answer 1 · 2011-06-23T02:25:00

I would take a bit different approach:

C#

public static string randdec(Random r, int l1, int l2)
{
  int L1= (int)Math.Pow(10, l1-1);
  int L2 = (int)Math.Pow(10, l2-1);
  int n1 = r.Next(L1, 10*L1);
  int n2 = r.Next(L2, 10*L2);
  return n1.ToString() + "." + n2.ToString();
}

that you may use this way

C#

public static void Main()
{
  Random r = new Random();
  for (int n = 0; n < 10; n++)
    Console.WriteLine(randdec(r,8,2));
}