How to Get Rectangle Top Left Position inside the Canvas.

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Hello Guys I am working on silverlight application this application is Basically image edittin so I have Canvas and inside the canvas I have a two child one is Image and Second is Rectange so I am Panning the Image and my Canvas is Fix size so how i'll get the Rectangle Top Left Position.

I had tried with Canvas.GetTop(myRectangle); but this will give me the some wrong value and Canvas.GetLet(myRectangle); it is also give me the same value so how I can resolve this problem..!!

My XAML is like this..

<canvas>
     x:Name="myCanvas"
     Grid.Row="1"
      ScrollViewer.HorizontalScrollBarVisibility="Visible"
      ScrollViewer.VerticalScrollBarVisibility="Visible"
     Grid.Column="0"
     Width="{Binding ElementName=imgEdit,Path=ActualWidth}"
     Height="{Binding ElementName=imgEdit,Path=ActualHeight}"
     Grid.ColumnSpan="2"
     HorizontalAlignment="Center"
     VerticalAlignment="Center">


     <!--Width="490"
             Height="490"-->

     <Image x:Name="imgEdit"
             Cursor="Hand"
             Stretch="Uniform"
             MouseLeftButtonDown="imgEdit_MouseLeftButtonDown"
             MouseMove="imgEdit_MouseMove"
             MouseLeftButtonUp="imgEdit_MouseLeftButtonUp"
             HorizontalAlignment="Center"
             VerticalAlignment="Center"
             RenderTransformOrigin="0.5, 0.5"
             >

             <Image.Effect>
                 <l:briconeffect xmlns:l="#unknown">
                         Brightness="{Binding ElementName=bVal, Path=Value}"
                         Contrast="{Binding ElementName=cVal, Path=Value}"
                         Gamma="{Binding ElementName=gVal,Path=Value}"
                         RedRatio="{Binding ElementName=rVal,Path=Value}"
                         BlueRatio="{Binding ElementName=blueVal,Path=Value}"
                         GreenRatio="{Binding ElementName=greenVal,Path=Value}"/>
             </Image.Effect>

             <Image.RenderTransform>

                 <transformgroup>
                     <rotatetransform x:name="Rotator" xmlns:x="#unknown">
                         <rotatetransform.angle>
                             <binding elementname="sldVerHorizontal" path="Value" mode="TwoWay" />
                         </rotatetransform.angle>
                     </rotatetransform>

                     <scaletransform x:name="Scale" xmlns:x="#unknown">
                         <scaletransform.scalex>
                             <binding elementname="sldZoomInOut" path="Value" mode="TwoWay" />
                         </scaletransform.scalex>
                         <scaletransform.scaley>
                             <binding elementname="sldZoomInOut" path="Value" mode="TwoWay" />
                         </scaletransform.scaley>
                     </scaletransform>
                 </transformgroup>
             </Image.RenderTransform>
         </Image>

     <border>
             Grid.Row="1"
             Grid.ColumnSpan="2"
             x:Name="maskBorder"
             BorderBrush="Green"
             BorderThickness="5"
             Width="200"
             Height="200"
             Cursor="Hand"
             HorizontalAlignment="Center"
             VerticalAlignment="Center"
             >
                 <!--Canvas.Top="150"
                 Canvas.Left="150"-->

         <rectangle>
                 Grid.Row="1"
                 Grid.ColumnSpan="2"
                 x:Name="maskRect"
                 Width="200"
                 Height="200"
                 HorizontalAlignment="Center"
                 VerticalAlignment="Center"
                 Cursor="Hand"
                 >
         </rectangle>
     </border>

 </l:briconeffect></canvas>

Posted 11-Jun-11 8:16am

Jitendra.Jadav

Updated 13-Jun-11 5:16am

v3

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[no name] 11-Jun-11 15:23pm

In my opinion the only thing you have is the canvas. Inside this canvas, canvas does not organize you anything…in other words you are responsible where your image is located and also your rectangle (what ever you mean with “…and a rectangle”….because there are a lot of possible rectangles inside a canvas, depending on it’s size ;) )

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Valery Possoz · Answer 1 · 2011-06-11T13:45:00

Hello,

The following code works perfectly:

A very simple Silverlight application with a Canvas, two children, an image and a rectangle.

This is the Xaml:

XML

<UserControl x:Class="SilverlightApplication2.MainPage"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
    xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
    mc:Ignorable="d"
    d:DesignHeight="300" d:DesignWidth="400">

    <Grid x:Name="LayoutRoot" Background="White">
        <Canvas Height="163" HorizontalAlignment="Left" Margin="54,69,0,0" Name="canvas1" VerticalAlignment="Top" Width="286">
            <Image Canvas.Left="30" Canvas.Top="25" Height="91" Name="image1" Stretch="Fill" Width="116" Source="/SilverlightApplication2;component/Images/diplodocus2.jpg" />
            <Rectangle Canvas.Left="186" Canvas.Top="68" Height="69" Name="rectangle1" Stroke="Black" StrokeThickness="1" Width="94" />
        </Canvas>
        <Button Content="Button" Height="23" HorizontalAlignment="Left" Margin="208,259,0,0" Name="button1" VerticalAlignment="Top" Width="75" Click="button1_Click" />
    </Grid>
</UserControl>

Ans this is the code behind:

C#

private void button1_Click(object sender, RoutedEventArgs e)
{
    foreach (var item in this.canvas1.Children)
    {
        double X = Canvas.GetLeft((UIElement)item);
    }
}

When the code executes Canvas.GetLeft returns the correct values.

Hope it helps.

Valery.