contextMenu based on xml element in treeView

Question

4.00/5 (1 vote)

See more:

After two days of googling and searching I give it up. Seems to me it is becoming big challenge :)

So I want to set two different context menus based on xml element name.

Lets say for group Add group and for document Add document

Prefering to do it in xaml without behind code.

One context menu should be when group element is right clicked other one when document element is clicked.

I have fairly simple xml structure:

XML

<?xml version="1.0" encoding="utf-8"?>
<docspacket>
  <packet>
    <group>
      <name>Home group</name>
        <group>
          <name>Other group</name>
          <document>
            <name>doc1</name>
          </document>
          <document>
            <name>doc2</name>
          </document>
        </group>
      <document>
        <name>doc1</name>
      </document>
      <document>
        <name>doc2</name>
      </document>
    </group>
  </packet>
</docspacket>

So my treeView have HierachicalDataView:

XML

<Grid.Resources>
            <HierarchicalDataTemplate x:Key="Group" ItemsSource="{Binding XPath=./*[name]}">
                <TextBlock Text="{Binding XPath=name}" />
            </HierarchicalDataTemplate>
            <XmlDataProvider x:Key="XmlNodeList" XPath="/docspacket/packet/*" Source="C:\Users\home\Documents\Visual Studio 2010\Projects\SimpleXMLparser\SimpleXMLparser\bin\Debug\XMLFile2.xml"/>
        </Grid.Resources>

And treeView control:

<TreeView ItemTemplate="{StaticResource Group}" ItemsSource="{Binding Source={StaticResource XmlNodeList}}" Height="229" HorizontalAlignment="Left" Margin="254,41,0,0" Name="treeView1" VerticalAlignment="Top" Width="404" SelectedItemChanged="treeView1_SelectedItemChanged" />

So maybe someone knows how should I implement such functionality?

Posted 20-Apr-11 4:05am

evaldas86

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sergey Alexandrovich Kryukov · Accepted Answer · 2011-04-20T08:08:00

The best approach would be using only one single Context Menu instance per Tree View control (or even a set of controls). The set of items if their states (IsEnabled, IsVisible, etc.) should be modified in the handle of the event System.Windows.Controls.ContextMenu.ContextMenuOpening (at the moment of processing the menu is not yet visible which is important). I would also prefer changing menu items property over re-populating of the items — it would give you a bit better performance, but more importantly would help to avoid some bugs.

I understand, you menu should look different for different Tree View Node. There is another trick: put all data relevant to the preparation of the Context Menu in the handler of System.Windows.Controls.ContextMenu.ContextMenuOpening. It should be some reference type as this data can be shared among many items.

—SA