Showing multiple Advertisement in one page

Please try this....
Code behind::

public partial class AdRotator : System.Web.UI.Page
{
int i = 0;
protected void Page_Load(object sender, EventArgs e)
{
if (!Page.IsPostBack)
{
DataSet ds = new DataSet();
string filePath = Server.MapPath("~/XMLFile1.xml");
ds.ReadXml(filePath);
DataList1.DataSource = ds;
DataList1.DataBind();
}
}
protected void AdRotator1_AdCreated(object sender, AdCreatedEventArgs e)
{
AdRotator _adRotator = (AdRotator)sender;
DataList _dataList = (DataList)(_adRotator.Parent.Parent);
Label lbldesc = (Label)_dataList .Items[i].FindControl("Label1");
if (lbldesc != null)
lbldesc.Text = e.AdProperties["AlternateText"].ToString();
Label lbldesc1 = (Label)_dataList .Items[i++].FindControl("Label2");
if (lbldesc1 != null)
lbldesc1.Text = e.AdProperties["id"].ToString();
}
}

Html Code::
<div>
<asp:DataList ID="DataList1" runat="server"
>
<HeaderTemplate>
<td> Advertisment</td>
<td>Description</td>
</HeaderTemplate>

<ItemTemplate>

<td>
<asp:AdRotator ID="AdRotator1" AdvertisementFile="~/XMLFile1.xml" target="_self"
runat="server" OnAdCreated="AdRotator1_AdCreated" />
</td>
<td>
<asp:Label ID="Label1" runat="server" ></asp:Label> //Display Description
</td>
<td>
<asp:Label ID="Label2" runat="server" ></asp:Label> //display ID
</td>

</ItemTemplate>
</asp:DataList>
</div>I hope it will work for you.
Please let me know, If you have questions.
Thanks,
Manisha Patel