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Hello,

I want the name of library in C# that generates random numbers with different distributions.

Thanks
Posted
Updated 31-Mar-11 18:18pm
v2

## Solution 5

You may generate the number with the `uniform` distribution provided by the standard `Random` class and then obtain the correnspondig number of another distribution 'simply' equating the values of the two cumulative functions.

Sergey Alexandrovich Kryukov 7-Mar-13 13:02pm
The idea is correct, but, look at the level of other answers. Do you think anyone (I don't know about OP who apparently knows better then those "experts") can understand your correct words?
Maybe it needs further explanation. Second half of the answer is really unclear. I voted 4 for now...
—SA
Xmen Real 7-Mar-13 13:19pm
There is no need to comment a 2 years old answer just to get reputation points.
CPallini 7-Mar-13 13:42pm
No, I know his honest interest.
Sergey Alexandrovich Kryukov 7-Mar-13 14:03pm
Thank you very much, Carlo.

I came to this page tracing posts of one another member, led by his today's post. But I actually don't need any excuses. I reasonably assume that I can comment any post I choose to comment.

To Xmen: do you think you are more free than others, dear? How can you accuse other people on such a ridiculous reason?
You can a free to post your baseless accusations, but, by some reason, I should not comment all the mistake people do here, only for the sake of helping other people to get knowledge, it that how you think?
This is absolutely indecent, to tell you the least.

—SA
Xmen Real 7-Mar-13 21:16pm
Nobody stops you from commenting, but why comment after years passed, I wouldn't mind if you have commented that time or downvoted me, but now ? AYFKM ?

## Solution 2

You can use this:

```int randomNumber(int min, int max)
{
Random rd = new Random()
return rd.Next(min,max);
}

Method will return a number from min to max```

Regards,

Sergey Alexandrovich Kryukov 7-Mar-13 12:56pm
It won't work correctly this way. Random should be instantiated only once in the Application Domain. This is very important.
You can construct it in declared class, and instantiate it only once, etc.
Besides, it does not resolve the problem of required distribution.
Incorrect answer, should never be used.
—SA

## Solution 4

wizardzz 1-Jun-11 16:02pm
Isn't that pretty much what was posted a month ago?

## Solution 3

Try this one!

THis generates a unique sequence without the need for a random seed.

http://msdn.microsoft.com/en-us/library/system.security.cryptography.randomnumbergenerator.aspx[^]

Code example for file encryption using a random salt for the Rijndael algorithm:

```private void button2_Click(object sender, EventArgs e)
{
// Generate the "IV" and the salt for the password
RandomNumberGenerator rng = RandomNumberGenerator.Create();
byte[] IV = new byte[16];
byte[] salt = new byte[16];
rng.GetNonZeroBytes(IV);
rng.GetNonZeroBytes(salt);
Rijndael rijndaal = new RijndaelManaged();
rijndaal.IV = IV;
rijndaal.Key = key;
using (FileStream input = File.Open(_fileName, FileMode.Open))
{
{
using (FileStream output = File.Create(_fileName + ".crypted"))
{
using (CryptoStream encryptingStream =
new CryptoStream(output, rijndaal.CreateEncryptor(), CryptoStreamMode.Write))
{
// first write the salt and the IV
output.Write(salt, 0, 16);
output.Write(IV, 0, 16);
output.Flush();
using (StreamWriter writer = new StreamWriter(encryptingStream))
{
}
}
}
}
}
}
```

Happy coding ...

Regards, Perry

Sergey Alexandrovich Kryukov 7-Mar-13 13:03pm
Sorry, off-topic, maybe by accident. The only matching topic is "random"...
—SA
Perry Bruins 5-Jun-13 9:27am
Sergey,

The code example is only there to show the USAGE of the RandomNumberGenerator class, which generates cryptograhically strong random numbers, what the OP asked for in my opinion.

By the way, this topix is already years old, so maybe your comment is of topic?

Regards, perry