Recreate source infix expression from rpn posfix expression

Question

0.00/5 (No votes)

See more:

Hi,

Does anyone know the best way of recreating the source infix expression from the rpn equivalent - ie how to get from abc*+ to a*b+c. Somehow brackets have to be added back into the source.

Posted 12-Jan-11 23:59pm

Robin Baker

Add a Solution

2 solutions

Solution 1

Use anlr, here is an example that will help:
http://www.antlr.org/wiki/display/ANTLR3/Expression+evaluator[^]

Regards
Espen Harlinn

Posted 13-Jan-11 0:04am

Espen Harlinn

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Estys · Accepted Answer · 2011-01-13T00:08:00

Solution 2

A link to our competitors :
http://stackoverflow.com/questions/113424/converting-reverse-polish-notation[^]

Cheers

Posted 13-Jan-11 0:08am

Estys

Comments

Espen Harlinn 13-Jan-11 6:14am

5+ that shows the "why" part of the answer :)