How do I avoid nameerror in Python 3.7 class?

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errors

Python3.6

I am trying to write a program where the "except clause will run when the parameters are wrong but I am getting NameError when I am giving non-valid parameter. I wanted the print function to be run only when the parameters are correct but it is running even if the parameters are wrong and so I am getting error.
Can anyone suggest how can I get the output without getting the error?

My code is:

class Hotel:
    def __init__(self,room,catagory):
        if type(room) != int:
            raise TypeError()
        if type(catagory) != str:
            raise TypeError()
        self.room = room
        self.catagory = catagory
        self.catagories = {"A":"Elite","B":"Economy","C":"Regular"}
        self.rooms = ["0","1","2","3","4","5"]


    def getRoom(self):
        return self.room

    def getCatagory(self):

        return self.catagories.get(self.catagory)
    def __str__(self):
        return "%s and %s"%(self.rooms[self.room],self.catagories.get(self.catagory))

try:
    room1 = Hotel(a,"A")

except: 

    print("there's an error")


print (room1)

What I have tried:

I have tried to indent the print line inside and outside of the except condition but neither of the way worked.