How do I create a treeview that reads all nodes/childnodes from active directory.

Question

0.00/5 (No votes)

See more:

Hi,

I'm trying to re-create my AD-structure with treeview.

I have used the example code from the user Smirnov: Active Directory Tree View Emulation | The ASP.NET Forums[^]

A very good example, thank you!

This is my problem:
This code works for the first two levels of treeview but later it becomes complicated for a beginner like me. I have tried to add node position in the OU-name for debugging purposes. Could someone please show me how to do this. :)
I guess I'm trying to solve this problem with the wrong method. There must be a general solution for adding all nodes and all childnodes from Active Directory. Later I will try to add computers also.

AD-structure| Flickr[^]

Application output[^]

using System;
using System.Collections.Generic;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.DirectoryServices;

namespace tree2
{
    public partial class Form1 : Form
    {
        int n = 0;
        int n2 = 0;
        int n3 = 0;
        string server;
        string level1;
        public Form1()
        {
            InitializeComponent();
            server = "LDAP://servername"; 
            level1 = "OU=MyCompany,OU=Companys,dc=my_dc,dc=local";
            GetAllNodes();
            
        }
        private void GetAllNodes()
        {       
            GetNodes(level1, 0);
        }
		
		// Modified code from Smirnov at https://forums.asp.net/post/4381459.aspx
        private void GetNodes(string path, int level)
        {
            using (DirectoryEntry entryToQuery = new DirectoryEntry(server + path))
            {
                DirectorySearcher ouSearch = new DirectorySearcher(entryToQuery);
                ouSearch.Filter = "(objectClass=organizationalUnit)";
                ouSearch.SearchScope = SearchScope.OneLevel;
                ouSearch.PropertiesToLoad.Add("name");

                SearchResultCollection allOUS = ouSearch.FindAll();

                foreach (SearchResult oneResult in allOUS)
                {
                    string ou = oneResult.Properties["name"][0].ToString();
                    string prefix = string.Empty;
                    
                    for (int i = 0; i < level; i++)
                    {
                        prefix += "*";
                    }
                    outbox.AppendText(prefix + ou + Environment.NewLine);
                    
                    int stars = countstars(prefix);
                    if (stars == 0) treeView1.Nodes.Add(ou);
                    if (stars == 1)
                    {
                        treeView1.Nodes[0].Nodes.Add(ou + " 0");
                        n++;
                    }
                    if (stars == 2)
                    {
                        treeView1.Nodes[0].Nodes[n-1].Nodes.Add(ou+" 0." + (n - 1).ToString()); 
                        n2++;
                    }
                    if (stars == 3)
                    {
                        // Not working...
                        // treeView1.Nodes[0].Nodes[n2].Nodes[0].Nodes.Add(ou + " 0." + (n2).ToString() + ".0"); 
                        n3++;
                    }

                    GetNodes("OU=" + ou + "," + path, level + 1);
                    
                }
            }
        }
        int countstars(string a)
        {
            int stars = 0;
            for (int i = 0; i < a.Length; i++)
            {
                if (a[i] == '*') stars++;
            }
            return stars;
        }

    }
}

What I have tried:

I have tried different approaches.
* Working with previous, this and next OU and decide where to put it in Treeview.
* I have tried debugging and add some local variables but it gets very messy.
* I have tried with parent node

Posted 16-Feb-19 5:59am

Member 3903277

Updated 16-Feb-19 15:04pm

Add a Solution

Comments

[no name] 16-Feb-19 14:47pm

You should get all the data first, "look" at it, then load it.

You'll get a better understanding of what's going on and what needs to be done.

It's not call ETL for nothing.

Member 3903277 17-Feb-19 5:12am

Thank you Gerry!

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

BillWoodruff · Accepted Answer · 2019-02-16T15:04:00

Note: I do not have a network to experiment with. Attached is some generic code to map a text file where the line structure reflects a tree structure with some text-delimiter repeated to indicate node level: note, this is code I wrote some time ago, and does not include robust error-checking; use as is at your own risk.

Suggest you review: [^]

The code here is, imho, simpler, and, I think can be easily adapted by you: [^]

And, CodeProject is your friend: start here: [^]

also see: [^], [^], [^]

Code example:

using System;
using System.Collections.Generic;
using System.Windows.Forms;

namespace YourNameSpace
{
    public static class StringToTreeView
    {
        private static char[] linesplitter; 

        private static TreeNode node;

        public static Dictionary<int, TreeNode> levelToNode = new Dictionary<int, TreeNode>();

        public static void Map(string source, char linesplit, char levelindicator, ref TreeView tv)
        {
            levelToNode.Clear();

            string[] lines = source.Split(new char[] { linesplit }, StringSplitOptions.RemoveEmptyEntries);

            TreeNode parentNode;

            for (int i = 0; i < lines.Length; i++)
            {
                string line = lines[i];
                string trimmed = line.TrimStart(levelindicator);

                // fast as Linq !
                // https://stackoverflow.com/a/541994/133321
                int level = line.Length - trimmed.Length;

                node = new TreeNode(trimmed);

                levelToNode[level] = node;

                if (level == 0)
                {
                    tv.Nodes.Add(node);
                }
                else 
                {
                    if (levelToNode.TryGetValue(level - 1, out parentNode))
                    {
                        parentNode.Nodes.Add(node);
                    }
                    else
                    {
                        throw new AccessViolationException($"\r\nerror in node definition: level exceeds current use {node.Text}\r\n");
                    }
                }
            }
        }
    }
}

A usage example:

string src = @"one,*two,**three,four,*five,**six,***seven,****eight,**nine";
            StringToTreeView.Map(src, ',', '*', ref YOURTREEVIEW);