Retrive record from accessdatabase and dispaly in label in ASP.NET

Question

1.00/5 (1 vote)

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onbutton click label will show next record from the accessdata base

i want to know - on buttonclick moving to next record and show it in label.
i will try but that only show 1st record or lastracord.

What I have tried:

using System.Data.OleDb;

namespace webfeedback
{
    public partial class _operator : System.Web.UI.Page
    {
        int i;
        int qn=1;
       protected void Page_Load(object sender, EventArgs e)
        {
            qn = i;
          
                OleDbConnection con = new OleDbConnection(@"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=E:\applab\webfeedback\feedback.accdb");
                con.Open();
                string cs = "select * from operator_question";
                OleDbCommand cmd = new OleDbCommand(cs, con);
                OleDbDataReader reader = cmd.ExecuteReader();
                qn = i;
                int count = reader.FieldCount;
                while (qn < 20)
                {
                    if (reader.Read())
                    {
                        Label1.Text = reader["question_number"].ToString();
                        Label2.Text = reader["question"].ToString();
                    }
                }
        }
        protected void Button1_Click(object sender, EventArgs e)
        {
            
            i = qn++;
        }

    
    }

Posted 5-Jan-19 19:41pm

Member 14109245

Updated 5-Jan-19 23:02pm

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3 solutions

Solution 2

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data.SqlClient;
using System.Data;
using System.Configuration;
public partial class deleteproduct : System.Web.UI.Page
{
    SqlConnection con = new SqlConnection(@"data source=(local);initial catalog=Mob;integrated security=true");
    protected void Page_Load(object sender, EventArgs e)
    {
        Label1.Visible = false;
        Label2.Visible = false;
        Label3.Visible = false;
        Label4.Visible = false;
        Label5.Visible = false;
        Label6.Visible = false;
        Label7.Visible = false;
        Label8.Visible = false;
        Label9.Visible = false;
        Label10.Visible = false;
        Label11.Visible = false;
        Label12.Visible = false;
        Label13.Visible = false;
        Label14.Visible = false;
        Label15.Visible = false;
        Label16.Visible = false;
        Label17.Visible = false;
        Image1.Visible = false;
        Button1.Visible = false;
    }
    protected void DropDownList1_SelectedIndexChanged(object sender, EventArgs e)
    {
        con.Open();
        string query = "select ProductName,Model,Display,Camera,ProductImage,Sim,Price,OS,Description from Table_1 where ProductID='" + DropDownList1.Text + "'";
     SqlCommand    cmd = new SqlCommand(query, con);
        cmd.CommandType = CommandType.Text;
     IDataReader  dr = cmd.ExecuteReader();

        while (dr.Read())
        {
            Label6.Text = dr["ProductName"].ToString();
            Label7.Text = dr["Model"].ToString();
            Label8.Text = dr["Display"].ToString();
            Label9.Text = dr["Camera"].ToString();
           Image1.ImageUrl = dr["ProductImage"].ToString();
           Label14.Text = dr["Sim"].ToString();
           Label15.Text = dr["Price"].ToString();
           Label16.Text = dr["OS"].ToString();
           Label17.Text = dr["Description"].ToString();

        }

        dr.Close();
        Label1.Visible = true;
        Label2.Visible = true;
        Label3.Visible = true;
        Label4.Visible = true;
        Label5.Visible = true;
        Label6.Visible = true;
        Label7.Visible = true;
        Label8.Visible = true;
        Label9.Visible = true;
        Label10.Visible = true;
        Label11.Visible = true;
        Label12.Visible = true;
        Label13.Visible = true;
        Label14.Visible = true;
        Label15.Visible = true;
        Label16.Visible = true;
        Label17.Visible = true;
        Image1.Visible = true;
        Button1.Visible = true;
    }
}

By Arpit Upadhyay

Posted 5-Jan-19 23:00pm

Member 13756920

Solution 3

Insert Image with Data in Data Base Useing Asp.net

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data.SqlClient;
public partial class addproduct : System.Web.UI.Page
{
    SqlConnection con = new SqlConnection(@"Data Source=(local);Initial Catalog=Mob;Integrated Security=True");
    protected void Page_Load(object sender, EventArgs e)
    {
        Label1.Visible = false;
    }
    protected void Button1_Click(object sender, EventArgs e)
    {
        if (FileUpload1.HasFile)
        {
            string strname = FileUpload1.FileName.ToString();
            FileUpload1.PostedFile.SaveAs(Server.MapPath("~/image/") + strname);
            con.Open();
            SqlCommand cmd = new SqlCommand("insert into Table_1 values('" + TextBox1.Text + "','" + TextBox2.Text + "','" + TextBox3.Text + "','" + TextBox4.Text + "','" + strname + "','" + DropDownList1.Text + "','" + TextBox6.Text + "','" + TextBox7.Text + "','" + TextBox8.Text + "')", con);
            cmd.ExecuteNonQuery();
            con.Close();
            Label1.Visible = true;
            Label1.Text = "Record Uploaded successfully!!!";
           
        }
        else
        {
            Label1.Visible = true;
            Label1.Text = "Plz upload the Record!!!!";
        }  
    }
}

By: Arpit Upadhyay

Posted 5-Jan-19 23:02pm

Member 13756920

Updated 5-Jan-19 23:03pm

v4

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AnkushK1 · Accepted Answer · 2019-01-05T22:19:00

I am not sure how the above code is working for you, it should have initiated an infinite loop in page load. However, an ideal solution would be to have a global dictionary type variable and save all of your database data, on button click just traverse through that. Also, it is not a good approach to keep the db connection open.