How do you declare number of cin's. If you know what I mean

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Hi Everyone,

I have a problem. How do you declare number of cin's. If you know what I mean.

Eg.

User Input: 5

5 cin's (user has to input 5 numbers)

User Input: 20 12 13 14 15

User Input: 7

7 cin's (user has to input 7 numbers)

User Input: 3 4 5 6 7 8 9

What I have tried:

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Posted 30-Dec-18 13:41pm

Member 14081190

Updated 30-Dec-18 13:50pm

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Rick York · Answer 1 · 2018-12-30T13:51:00

Have you got to loops yet? A for loop would work well to do this. Here is a for loop :

for( int n = 0; n < inputCount; ++n )
{
   // do something inputCount times here
}

If you want to input some numbers what are you going to do with them? I am going to guess you want to save them. You need a place to save them so this will allocate some:

int * inputs = new int[inputCount];

You can combine these two operations, prompt for entry, and save the input like this :

int * inputs = new int[inputCount];
for( int n = 0; n < inputCount; ++n )
{
    cout << "enter input " << n+1 << " : ";
    inputs[n] << cin;
}

// do something else with the input here

delete [] inputs;   // release allocated memory