Python code-> C++ code

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Python

C++11

Please change this code to c++

from random import randint

R, L, D, U, SOLVE = 1, 2, 4, 8, 16RLDU = [R, L, D, U]MOVE_X = [0, 0, 1, -1]
MOVE_Y = [1, -1, 0, 0]



def make_way(x1, y1, x2, y2, org_maze, solve=0):
x_size = len(org_maze)
y_size = len(org_maze[0])
cnt = 0


while cnt < x_size * y_size:
cnt += 1
x, y = x1, y1
maze = [list(row) for row in org_maze]

visited = []
while True:
direction = randint(0, 3)
if direction in visited:
continue
else:
visited += [direction]

next_x = x + MOVE_X[direction]
next_y = y + MOVE_Y[direction]





if -1 < next_x < x_size and -1 < next_y < y_size and not is_way_xy(next_x, next_y, maze):

maze[x][y] |= RLDU[direction]
if solve == SOLVE:
maze[x][y] |= SOLVE
x = next_x
y = next_y
visited = []
if next_x == x2 and next_y == y2:
return maze


if len(visited) == 4:
break


def random_xy(maze, is_way):
x_size = len(maze)
y_size = len(maze[0])
while True:
x = randint(0, x_size - 1)
y = randint(0, y_size - 1)
if (x == 0 and y == 0) or (x == x_size - 1 and y == y_size - 1):
continue
if is_way and maze[x][y] != 0:
return x, y
if not is_way and not is_way_xy(x, y, maze):
return x, y


def is_way_xy(x, y, maze):
if maze[x][y] != 0:
return True
else:

if y > 0 and maze[x][y - 1] & R:
return True

if y < y_size - 1 and maze[x][y + 1] & L:
return True

if x > 0 and maze[x - 1][y] & D:
return True

if x < x_size - 1 and maze[x + 1][y] & U:
return True
return False



x_size = 10
y_size = 10
wrong_way = 10
maze = [[0] * y_size for i in range(x_size)]


maze = make_way(0, 0, x_size - 1, y_size - 1, maze, SOLVE)


for i in range(wrong_way):
while True:

x1, y1 = random_xy(maze, True)

x2, y2 = random_xy(maze, False)
next_maze = make_way(x1, y1, x2, y2, maze)
if next_maze:
break
maze = next_maze

What I have tried:

i don't know python.
please help me.