How do I auto increment an 8-digit reference number?

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SQL-Server-2012

Hello,

A newbie question.

Lets say I need to create a database called 'Cars' and I want to 'auto increment' the 'CarId' column.

I would use the following statement for this particular column:

SQL

CarId int IDENTITY(1,1) Primary Key

Every time a new record is inserted into the database it would add a number to the CarId as 1, 2, 3, 4 and so on.

What if I wanted to allocate a random 8 digit 'CarId' number or an ordered 8-digit 'CarId' number, what would be the best way of going about this?

Please can someone advise.

Thanks

What I have tried:

I'm learning to work with SQL Server 2012 Express

Posted 7-Aug-18 23:57pm

Skipton Corp

Updated 8-Aug-18 1:08am

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Skipton Corp 9-Aug-18 3:58am

Thank you for the solution.

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OriginalGriff · Accepted Answer · 2018-08-08T01:09:00

Random is a bad idea: they clash far too often. If you want "random ids" then use UNIQUEIDENTIFIER instead, but they are most definitely not 8 digit!

Orders is what you get from IDENTITY, and integers are always potentially 8 digit (just they start with 7 or them having leading zeros.
One way to get a "true" 8 bit sequence is to define your column as

SQL

CarID INT IDENTITY(10000000, 1) PRIMARY KEY

Which means they start from 10,000,000 and go up from there.