How can we redirect to same view without data loss

Question

1.00/5 (2 votes)

See more:

I have two textbox on same view on project when I first time load we provide value on textbox from controller using model.name its show in view than i click on button another textbox show other value model.age but the model.name value is remove I want both the values in textbox

What I have tried:

<pre>namespace WebApplication2.Controllers
{
    public class HomeController : Controller
    {
        // GET: Home

        Class1 cs = new Class1();
        public ActionResult Index()
        {
            if(TempData["A"]==null)
            {
                
                cs.name = "hi";
                TempData["A"] = "B";
            }
            
            return View(cs);
        }

        public ActionResult A()
        {
           cs.age ="hello";
            //return RedirectToAction("Index",cs);
            return View("Index", cs);

        }


        }
}

Posted 3-Aug-18 0:12am

Member 13909869

Updated 5-Aug-18 2:52am

Add a Solution

Comments

F-ES Sitecore 3-Aug-18 6:46am

You have to make sure the button you click is submitting a form and you add the model to the action. So if your button submits to "A";

public ActionResult A(Class1 model)

If you have properly bound your textbox to Model.name in the view then "model" in "A" will have that data also. Without seeing your view it's impossible to answer.

You really need to get a better basic understanding of MVC though, I suggest you go through a book or some tutorials like the "MVC Music Store".

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

EasyPedia · Answer 1 · 2018-08-05T02:52:00

I am sure about your view : -
you have to bind back your model on each request to preserve its value.
Your code would be something like:-

Home Controller

    public class HomeController : Controller
    {       
        Class1 cs = new Class1();
        [HttpGet]
        public ActionResult Index(Class1 model)
        {
            cs.name = "hi";
            if (TempData["A"] == null)
            {
                TempData["A"] = "B";
            }

            return View(cs);
        }
       
        public ActionResult A(Class1 model)
        {
            model.age = "hello";
            return RedirectToAction("Index", model);
            //return View("Index", cs);

        }      
    }

Index View

    <pre>@using Articles.Models
    @model Class1
    @{
       Layout = null;
    }

    <!DOCTYPE html>
 
    <html>
    <head>
        <meta name="viewport" content="width=device-width" />
        <title>Index</title>
    </head>
    <body>
        @using (Html.BeginForm("A", "Home", FormMethod.Post))
        {
            <div>
                @Html.LabelFor(model => model.name)   
                @Html.EditorFor(model => model.name)
            
                <br />
                @Html.LabelFor(model => model.age)     
                @Html.EditorFor(model => model.age)
            </div>
            <div class="options">
               <input type="submit" name="save" class="btn btn-success" value="Save" />
            </div>
        }
    </body>
    </html>

KarstenK · Answer 2 · 2018-08-03T00:24:00

Solution 1

You need to switch to a model driven UI. Both ends of your UI can manipulate the model and fetch data from it to display it.

=> Create a data model class and handle its changes and display in the UI

Posted 3-Aug-18 0:24am

KarstenK