How to date difference millsecond

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i need date difference mill second

select DATEADD(Day, DATEDIFF(Day, 0, getdate()) - 1, -0.0000001)

2018-07-23 23:59:59.993

but i need as 2018-07-23 23:59:59.999

What I have tried:

I have tried as added zero

select DATEADD(Day, DATEDIFF(Day, 0, getdate()) - 1, -0.00000001)

2018-07-24 00:00:00.000

but i excepted as

2018-07-23 23:59:59.999

Posted 24-Jul-18 20:37pm

Member 12640353

Updated 25-Jul-18 4:16am

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Richard Deeming · Answer 1 · 2018-07-25T04:14:00

Assuming SQL 2008 or higher, you'll need to use the new datetime2(7) type[^].

SQL

SELECT DateAdd(millisecond, -1, Cast(DateAdd(day, -1, Cast(SysDateTime() As date)) As datetime2(7)));
-- Output: 2018-07-23 23:59:59.9990000

Breaking that down:

SQL

DECLARE @Now datetime2(7) = SysDateTime();                                   -- Get the current date and time
DECLARE @Today date = Cast(@Now As date);                                    -- Remove the time part
DECLARE @Yesterday date = DateAdd(day, -1, @Today);                          -- Subtract one day
DECLARE @YesterdayDateTime datetime2(7) = Cast(@Yesterday As datetime2(7));  -- Need a datetime2 to subtract time units
DECLARE @Result datetime2(7) = DateAdd(millisecond, -1, @YesterdayDateTime); -- Subtract one millisecond

OriginalGriff · Answer 2 · 2018-07-24T21:31:00

Solution 1

You can't: the DATETIME type in SQL is not stored as milliseconds, it is stored as a number of ticks since a specific point in time, and a tick is normally 31.250 milliseconds (but is computer dependant): @@TIMETICKS[^]

Posted 24-Jul-18 21:31pm

OriginalGriff