How to get all times greater than a particular time in SQL

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SQL-Server-2016

Hi all,

I have a table with a field ie starttimes . What I need is that , I need to get all the starttimes that is greater than a particular time . I have stored the time in varchar type.

What I have tried:

For example ,

StartTimes
1:00 AM    
2:00 AM  
3:00 AM      
4:00 AM  
7:00 AM 
1:00 PM
2:00 PM
3:00 PM

and so on .
If I select 7:00 AM , I need to get all the times greater than 7:00 AM ie all times in time field within 12 Hrs ie from 7:00 AM TO 11:59 PM.How to do this.
Any help will be really appreciated .Thanks in Advance.

Posted 3-Jul-18 1:14am

Member 12926744

Updated 3-Jul-18 1:46am

CHill60

v2

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CHill60 3-Jul-18 7:38am

Easy answer is don't use Varchar type for Time ... use, er, Time

Maciej Los 3-Jul-18 10:57am

My virtual 5!

2 solutions

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CHill60 · Answer 1 · 2018-07-03T01:46:00

Using this sample data

create table #badway
(
	id integer identity(1,1),
	mytime varchar(8)
)
insert into #badway (mytime) values
('1:00 AM'),
('2:00 AM'),  
('3:00 AM'),      
('4:00 AM'),  
('7:00 AM'), 
('1:00 PM'),
('2:00 PM'),
('3:00 PM')

Then this query fits your criteria

SQL

select id, convert(time, mytime) from #badway
where convert(time, mytime) between '07:00:00' and '23:59:00'

Note the use of the 24hr clock.

As I said in my comment, you should use time column types to store times, not varchar, then there would be no need for the convert

Krunal Rohit · Answer 2 · 2018-07-03T01:39:00

Solution 1

Use SQL Server DATEPART() Function[^].

SQL

SELECT * FROM [your table] WHERE DATEPART(hh, [your date field]) = 7 --7 AM

KR

Posted 3-Jul-18 1:39am

Krunal Rohit

v2

Comments

CHill60 3-Jul-18 7:48am

You were closer with v1 of this solution. You actually mean

SELECT * FROM [your table] WHERE DATEPART(hh, [your date field]) >= 7