Change the first element in a list from string to date

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I have the following text file that has these lists :

Python

['2009-06-12 14:19:28 ', '0']
['2009-06-13 00:58:10 ', '0']
['2009-06-13 01:00:25 ', '0']
['2009-06-15 03:24:23 ', '0']
['2009-06-25 17:50:46 ', '0']
['2009-06-29 20:54:52 ', '0']
['2009-06-30 20:31:19 ', '0']
['2009-07-09 03:01:25 ', '0']
['2009-07-12 14:45:53 ', '0']
['2009-07-12 15:09:38 ', '0']

The second element is an integer, however, the first element is a string. I need the first element of each lis to be a date instead of string?

I tried this code:

Python

word[0]=datetime.strptime(word[0],'%Y/%m/%d %H:%M:%S')

but I get this error:

Python

ValueError: time data '2009-04-02 22:50:06 ' does not match format '%Y/%m/%d %H:%M:%S'

the current code I have that cleans the data is the following:

Python

with open('newdata.txt') as f:
    for line in f:
       tweet=re.sub(r'T\t',"",line)
       t=re.sub(r'W\t',"\/\/",tweet)
       data=t.split("\/\/")
       sentiment_value= s.sentiment(data[1])
       data.append(sentiment_value)

       words = [w.replace('pos', '1') for w in data]
       word=[w.replace('neg','0')for w in words]
       del word[1]
       print(word)

What I have tried:

I tried this code:

Python

word[0]=datetime.strptime(word[0].strip(),'%Y/%m/%d %H:%M:%S')

but I get this error:

Python

ValueError: time data '2009-04-02 22:50:06 ' does not match format '%Y/%m/%d %H:%M:%S'

Posted 20-Jun-18 19:11pm

Member 13647869

Updated 20-Jun-18 20:32pm

v2

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Comments

Richard MacCutchan 21-Jun-18 3:34am

You have hyphens (-) as separators in your date string, but forward slashes (/) in your format string.

Member 13647869 21-Jun-18 3:43am

i changed it to this:
word[0]=datetime.strptime(word[0],'%Y-%m-%d %H:%M:%S')

and got this:

ValueError: unconverted data remains:

Richard MacCutchan 21-Jun-18 3:46am

Look at your data, there is a space after the seconds field. Your format string must match exactly.

Member 13647869 21-Jun-18 3:46am

i have put that space, or do i have to remove that?

Richard MacCutchan 21-Jun-18 3:54am

Like I said above.

Member 13647869 21-Jun-18 3:55am

it is the exact format

Member 13647869 21-Jun-18 3:57am

ok i got it. it chnages but i get this,
[datetime.datetime(2009, 8, 31, 23, 58, 9), 1]
[datetime.datetime(2009, 8, 31, 23, 58, 9), 1]
[datetime.datetime(2009, 8, 31, 23, 58, 9), 1]

is there any way to remove the datetime? or is that like a standard outcome?

Richard MacCutchan 21-Jun-18 4:23am

I don't understand the question.

Member 13647869 21-Jun-18 5:31am

the words datime.datime, why are they added? like is this the format of a date?

Richard MacCutchan 21-Jun-18 7:10am

No idea. Please use the Improve question link above, and show the actual code that produces the output or error. We cannot guess what you are doing.

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Maciej Los · Answer 1 · 2018-06-20T20:21:00

Solution 1

On the first look... Seems you need to replace:

Python

dt = datetime.strptime("2009-04-02 22:50:06",'%Y/%m/%d %H:%M:%S')

with:

Python

dt = datetime.strptime("2009-04-02 22:50:06", "%Y-%m-%d %H:%M:%S")

See:
Converting Strings To Datetime[^]
8.1. datetime — Basic date and time types — Python 3.6.6rc1 documentation[^]

But... the documentation[^] states also:

Quote:
Calling strptime() with incomplete or ambiguous ISO 8601 directives will raise a ValueError.

(...)

Because the format depends on the current locale, care should be taken when making assumptions about the output value. Field orderings will vary (for example, “month/day/year” versus “day/month/year”), and the output may contain Unicode characters encoded using the locale’s default encoding (for example, if the current locale is ja_JP, the default encoding could be any one of eucJP, SJIS, or utf-8; use locale.getlocale() to determine the current locale’s encoding).

Posted 20-Jun-18 20:21pm

Maciej Los

Updated 20-Jun-18 22:05pm

v2

Comments

Member 13647869 21-Jun-18 2:30am

i tried it i got this error:

ValueError: time data '2009-04-02 22:50:06 ' does not match format '%y-%m-%d %H:%M:%S'

plus, i need to index the element of each list, because each list has a different date string in the first element

Member 13647869 21-Jun-18 2:32am

sorry, it seems that I have put a wrong sample of the text file I changed it

Richard MacCutchan 21-Jun-18 3:35am

Should be upper case (Y) for 4-digit year.

Maciej Los 21-Jun-18 4:05am

Thanks! Updated!
BTW: I'm not an expert of Python ;)

Richard MacCutchan 21-Jun-18 4:23am

You are now.

Maciej Los 21-Jun-18 5:09am

:laugh:

Member 13647869 21-Jun-18 6:08am

wow! that's how you become experts?! congrats Maciej Los =)

Maciej Los 21-Jun-18 6:11am

Thanks!
Follow the same way and you'll be an expert too :)

Member 13647869 21-Jun-18 6:17am

hahah, i really hope so!