Is using a contentcontrol breaking MVVM?

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Just a small question but i haven't found an answer to it so far today so i thought i'd just ask myself.

If i place a contentcontrol in my view with it's contents bound to a property, then build a DataGridView in my viewmodel and set that property to it is that breaking MVVM?

Basically my application needs to have a DataGrid that has different columns in different circumstances.

I have read about placing a DataGrid on the view then binding to a columncollection and using behaivours and such.

I felt using a contentcontrol would just be easier really but there must be a reason i can't find many (or any) information on weather that breaks MVVM or not.

What I have tried:

Goole, CodeProject, StackOverflow

Posted 13-Jun-18 8:29am

BeginnerCoderPete

Updated 13-Jun-18 9:36am

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[no name] 13-Jun-18 14:32pm

Read only?

BeginnerCoderPete 13-Jun-18 14:35pm

Yes it's a read only DataGrid.

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Gerry Schmitz · Answer 1 · 2018-06-13T09:37:00

Solution 1

Since it's "read-only", it's just a "widget".

It falls in the same category as an "image", "label", chart, "LED".

Treat them all (more or less) as place holders.

In fact, one should be able to swap your "grid" for a "chart" or any other "performance indicator", at any time, without sweating "mvvm".

Posted 13-Jun-18 9:37am

Gerry Schmitz

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BeginnerCoderPete 14-Jun-18 3:04am

But how do I change the columns as and when i need to through MVVM? Is what I'm wondering. Should I either build the grid in code and display it in a contentcontrol or place the Grid on my view and bind the columns to a colection?

[no name] 14-Jun-18 12:58pm

The "grid" itself is a "view": stripped of "logical" elements ("rows"; "columns"), you are left with text blocks, maybe check boxes; i.e. a "view".

So it is a view, or a "view - within - another view".

Bind to it's "own" model; or the "parent" view's model.

In either case "the code behind / model" isn't aware of the "grid" (i.e. "columns").