Quote:
Does this code to insert to a tree not work for empty trees?
First: read the code and particularly comments.
second: there is an easy way to know the answer, make a testing program that call the routine with a NULL tree and see if it works.
third: To help you understand what this code does and how it work, use the debugger and watch it.
Your code do not behave the way you expect, and you don't understand why !
There is an almost universal solution: Run your code on debugger step by step, inspect variables.
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't know what your is supposed to do, it don't find bugs, it just help you to by showing you what is going on. When the code don't do what is expected, you are close to a bug.
To see what your code is doing: Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.
Debugger - Wikipedia, the free encyclopedia[
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1.11 — Debugging your program (stepping and breakpoints) | Learn C++[
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The debugger is here to only show you what your code is doing and your task is to compare with what it should do.
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Learn to indent properly your code, it show its structure and it helps reading and understanding. It also helps spotting structures mistakes.
node* insert (node *p_tree, int key)
{
if ( p_tree == NULL )
{
node* p_new_tree = new node;
p_new_tree->p_left = NULL;
p_new_tree->p_right = NULL;
p_new_tree->key_value = key;
return p_new_tree;
}
if( key < p_tree->key_value )
{
p_tree->p_left = insert( p_tree->p_left, key );
}
else
{
p_tree->p_right = insert( p_tree->p_right, key );
}
return p_tree;
Professional programmer's editors have this feature and others ones such as parenthesis matching and syntax highlighting.
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