How to get the count of only occupied values in a table in SQL

Question

0.00/5 (No votes)

See more:

Hi all,

I have a table with some columns and values. I need the count of only occupied values excluding null values and empty field in one single query.Any help will be really appreciated .Thanks in advance.

What I have tried:

id     Name      mob            address      gender      Dob

1      Sara     9884436546       NULL          F         NULL
2      Math                      abc city      M         
3      Asyu      NULL                          NULL      1994-05-29

Here the o/p should be like this 
id 1 : Count =3
id 2:  count =3
id 3:  count =2

Posted 30-May-18 19:06pm

Member 12926744

Updated 30-May-18 22:55pm

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CHill60 · Answer 1 · 2018-05-30T22:56:00

Assuming that it is only this table you are interested in then this simple technique would work

SQL

;with x as 
(
	SELECT id, hasvalue = CASE WHEN ISNULL([Name],'') <> '' THEN 1 ELSE 0 END FROM #test
	UNION ALL
	SELECT id, hasvalue = CASE WHEN ISNULL(mob,'') <> '' THEN 1 ELSE 0 END FROM #test
	UNION ALL
	SELECT id, hasvalue = CASE WHEN ISNULL([address],'') <> '' THEN 1 ELSE 0 END FROM #test
	UNION ALL
	SELECT id, hasvalue = CASE WHEN ISNULL(gender,'') <> '' THEN 1 ELSE 0 END FROM #test
	UNION ALL
	SELECT id, hasvalue = CASE WHEN ISNULL(Dob,'') <> '' THEN 1 ELSE 0 END FROM #test
)
select id, SUM(hasvalue) from x group by id

Comments:
- I duplicated your table into #test, replace that with your table name
- You need to use UNION ALL - it won't work with just UNION (as duplicates will be removed)
- Your data had a blank (not NULL) date - I trust you have not stored that date in a varchar column!