How do I transform this lambda function into def format?

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I am trying to understand the details of this code do:

 prune = lambda tree : [prune(branch) for branch in tree if branch != []]

l = [[[[], []], [[], []]], [[], [], []]]
prune(l)

But i have not yet learnt the lambda function.

What I have tried:

I am trying to break it down to the def function format

def prune(tree):
    for branch in tree:
        if branch!=[]:
             prune(branch)
    return branch
print prune([[[[], []], [[], []]], [[], [], []]])

But it doesn't give the same result, what am I doing wrong?

Posted 6-May-18 5:51am

Member 13814092

Updated 6-May-18 6:37am

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Thomas Daniels · Accepted Answer · 2018-05-06T06:39:00

Solution 1

Python

def prune(tree):
    result = []
    for branch in tree:
        if branch != []:
            result.append(prune(branch))
    return result

You were almost there; the only step you missed, was adding the elements to a result list.

Posted 6-May-18 6:39am

Thomas Daniels

Comments

Maciej Los 6-May-18 16:12pm

5ed!