Xml transform query,

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Hi. No doubt an easy one to you experts.
I have an XML that I need to transform into another XML, taking some of the elements and writing to new elements etc...
I have cut the file down considerably, hopefully enough for you to point me in the right direction.

XML

<?xml version="1.0" encoding="utf-8"?>
<kmsg xmlns:env="http://xml.changedthisbit" xmlns="http://xml.changedthisbit">
  <header>
    <env:envelope>
      <env:payload>ORDER</env:payload>
      <env:cfcompany>01</env:cfcompany>
      <env:service>LIVE</env:service>
      <env:source branch="" endpoint="" machine="" password="" />
      <env:destination branch="0002" endpoint="" machine="" />
    </env:envelope>
  </header>
  <body>
    <Order xmlns="urn:schemas-basda-org:2000:purchaseOrder:xdr:3.01">
      <OrderDate>2012-08-08T09:40:00</OrderDate>
      <Extensions>
        <WebOrder>true</WebOrder>
      </Extensions>
      <OrderLine Action="Add" TypeCode="New" TypeDescription="New Item">
         <Product>
            <ProductId>1234</ProductId>
         </Product>
      </OrderLine>
      <OrderLine Action="Add" TypeCode="New" TypeDescription="New Item">
         <Product>
            <ProductId>9876</ProductId>
         </Product>
      </OrderLine>
    </Order>
   </body>
</kmsg>

I am having trouble simply just outputting the OrderDate. I just get this output.

XML

<?xml version="1.0" encoding="iso-8859-1"?>

I haven't started on the for each for the order lines....

Hoping you will be able to point me in the right direction, (I am filling the swear jar with every attempt I make). I know it must be something simple. Thanks in advance.

What I have tried:

I have this transform:-

XML

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
	<xsl:output encoding="iso-8859-1"/>
	<xsl:output method="xml" indent="yes" omit-xml-declaration="no"/>
	<xsl:template match="/">

	<header>
	</header>
	<body>
		<xsl:value-of select = "kmsg/body/Order/OrderDate"/>
	</body>
	</xsl:template>
</xsl:stylesheet>

Posted 13-Apr-18 6:40am

MKM_Matt

Updated 13-Apr-18 8:43am

Patrice T

v3

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RickZeeland · Answer 1 · 2018-04-13T07:35:00

I reformatted the xml to this:

<?xml version="1.0" encoding="utf-8"?>
  <body>
    <Order>
      <OrderDate>2012-08-08T09:40:00</OrderDate>
      <Extensions>
        <WebOrder>true</WebOrder>
      </Extensions>
      <OrderLine Action="Add" TypeCode="New" TypeDescription="New Item">
         <Product>
            <ProductId>1234</ProductId>
         </Product>
      </OrderLine>
      <OrderLine Action="Add" TypeCode="New" TypeDescription="New Item">
         <Product>
            <ProductId>9876</ProductId>
         </Product>
      </OrderLine>
    </Order>
   </body>

And then ran this code:

XElement _x = XElement.Load(@"order.xml");
var orders = from el in _x.Elements("Order") select el;

foreach (var order in orders)
{
    Debug.Print(order.Element("OrderDate").Value);
}

You could clean up the XML in an automated way like this:

 XDocument doc = XDocument.Load("order.xml");

 // Strip namespace...
 foreach (var node in doc.Root.Descendants()
                         .Where(n => n.Name.NamespaceName == "urn:schemas-basda-org:2000:purchaseOrder:xdr:3.01"))
 {
     // Remove the xmlns='' attribute.
     node.Attributes("xmlns").Remove();
     node.Name = node.Parent.Name.Namespace + node.Name.LocalName;
 }

Debug.Print(doc.ToString());     // Or doc.Save(...)