Problem with mysqli.

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PHP

MySQL

Parameter

I want to display a few records from my table, but there seems to be a problem with the mysqli part, these are the erros that keeps popping up;

Warning: mysqli_select_db() expects parameter 1 to be mysqli, string given in D:\xampp\htdocs\Project\add_employees.php on line 78

Warning: mysqli_query() expects parameter 1 to be mysqli, string given in D:\xampp\htdocs\Project\add_employees.php on line 79

Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, null given in D:\xampp\htdocs\Project\add_employees.php on line 90
ID Name Phone Number Date Employed Date Unemployed

Can someone explain what the errors mean, and what I'm doing wrong ?

<?PHP
          $conn = new mysqli("localhost","root","");
          mysqli_select_db("kz_komputer",$conn);
          $data = mysqli_query("SELECT * FROM employees",$conn);
          
          echo "<table>
          <tr>
            <th> ID</th>
            <th> Name</th>
            <th> Phone Number</th>
            <th> Date Employed</th>
            <th> Date Unemployed</th>
          </tr>";
          
          while($record = mysqli_fetch_array($data)){
            echo "<tr>";
            echo "<td>" . $record['id'] . "</td>";
            echo "<td>" . $recod['name'] . "</td>";
            echo "<td>" . $record['phone_number'] . "</td>";
            echo "<td>" . $record['date_employed'] . "</td>";
            echo "<td>" . $record['date_unemployed'] . "</td>";
            echo "</tr>";
          }
          echo "</table>";
          
          mysqli_close($conn);
?>

What I have tried:

$conn = new mysql("localhost","root","","kz_komputer");
$sql = "SELECT * FROM employees";
$data = mysql_query($sql,$conn);